【数学】【AOJ-41】Least Common Multiple

Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is
divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

Input

Input will consist of multiple problem instances. The first line of the input file will contain a single
integer indicating the number of problem instances. Each instance will consist of a single line of the
form m n1 n2 n3... nm where m is the number of integers in the set and n1 ...nm are the integers. All
integers will be positive and lie within the range of a 32-bit integer.

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie
in the range of a 32-bit integer.

Sample Input

Original

Transformed

2
3 5 7 15
6 4 10296 936 1287 792 1

 

Sample Output

105
10296

思路：

每两个两个求最小公倍数

 

参考代码：

#include <stdio.h>
int GCD(int a,int b)//最大公约数
{
	if(!b)
		return a;
	return GCD(b,a%b);
}

int LCM(int a,int b)//最小公倍数
{
	return a/GCD(a,b)*b;
}

int a[10000];

int main()
{
	int t;
	scanf("%d",&t);
	while(t--)
	{
		int n;
		scanf("%d",&n);
		int i;
		for(i=0;i<n;i++)
			scanf("%d",&a[i]);
		int temp=a[0];
		for(i=1;i<n;i++)
			temp=LCM(temp,a[i]);
		printf("%d
",temp);
	}
	return 0;
}