2015

偶数求和

总共n个偶数 一组m个数 求平均数

末尾不足m个 求平均数

#include <stdio.h>

int main(void)
{
    int n,m,i,j,s,p,q;
    while(scanf("%d %d",&n,&m))
    {
        s = p = q = 0;
        for(j =1,i = 2;i <= 2*n;i+=2)
        {
            s += i;
            if(j % m == 0)
            {
                printf("%d ",s/m);
                s = 0;
            }
            j++;
            if(n % m != 0 && i > 2 * (n / m + 1))
            {
                p += i;
                q++;
                if(i == 2*n)
                    printf("%d
",p / q);
            }
        }
        if(n % m == 0)
            printf("
");
    }
    return 0;
}

参考答案

#include <stdio.h>

int main(void)
{
    int i, n, m, b, c;

    while (scanf("%d%d", &n, &m) != EOF)
    {
        b = 2;
        c = 0;
        for (i = 0 ; i < n / m ; i++)
        {
            printf(c++ ? " %d" : "%d", b + m - 1);
            b += m * 2;
        }
        printf(n % m ? " %d
" : "
", b + n % m - 1);
    }

    return 0;
}