2023

有n个学生m个课程

求每个学生的平均分

求每个课程的平均分

求每个课程分数大于该课程平均分的人数

 

#include <stdio.h>
#include <math.h>

int main()
{
	int m, n, i, j, count,sum;
	while (scanf_s("%d%d", &n, &m))
	{
		count = sum = 0;
		double defen, pdefen[50][5] = { { 0 } };
		double p[50] = { 0 };
		double q[5] = { 0 };
		for (i = 0; i < n; i++)
		{
			for (j = 0; j < m; j++)
			{
				scanf_s("%lf",&defen);
				pdefen[i][j] = defen;
			}
		}
		for (i = 0; i < n; i++)
		{
			for (j = 0;j < m;j++)
			{
				p[i] += pdefen[i][j];
			}
			printf("%.2lf%c", p[i] / m, (i < n - 1 ? ' ' : '
'));
		}

		for (j = 0; j < m; j++)
		{
			for (i = 0; i < n; i++)
			{
				q[j] += pdefen[i][j];
			}
			printf("%.2lf%c", q[j] / n, (j < m - 1? ' ' : '
'));
		}
		for (i = 0; i < n; i++)
		{
			count = 0;
			for (j = 0; j < m && pdefen[i][j] >= q[j]/n; j++)
			{
					count++;
					if (count == m) sum++;
			}
		}
		printf("%d
", sum);
	}
	return 0;
}

　　

参考答案

#include <stdio.h>
#include <string.h>

int main(void)
{
    int n, m;
    int i, j;
    int t, d;
    int s[50];
    int c[5];
    int sc[50][5];

    while (scanf("%d%d", &n, &m) != EOF)
    {
        memset(s, 0, sizeof(s));
        memset(c, 0, sizeof(c));
        memset(sc, 0, sizeof(sc));
        for (i = 0 ; i < n ; i++)
        {
            for (j = 0 ; j < m ; j++)
            {
                scanf("%d", &sc[i][j]);
                c[j] += sc[i][j];
                s[i] += sc[i][j];
            }
        }
        for (i = 0 ; i < n ; i++)
            printf("%.2lf%c", s[i] * 1.0 / m, i < n - 1 ? ' ' : ' 
');
        for (i = 0 ; i < m ; i++)
            printf("%.2lf%c", c[i] * 1.0 / n, i < m - 1 ? ' ' : ' 
');
        for (t = i = 0 ; i < n ; i++)
        {
            for (d = 1, j = 0 ; j < m ; j++)
            {
                if (sc[i][j] < 1.0 * c[j] / n)
                {
                    d = 0;
                    break;
                }
            }
            if (d) t++;
        }
        printf("%d

", t);
    }

    return 0;
}