九度OnlineJudge之1010 A + B

题目描述：                       

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

输入：                       

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

输出：                       

对每个测试用例输出1行,即A+B的值.

样例输入：                       

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

样例输出：                       

3
90
96

#include <iostream>
#include <string>
#include <vector>
#include <cmath>
using namespace std;

inline int  getInt(string  str)
{
	if (str=="zero")  return 0;
	if (str=="one")  return 1;
	if (str=="two")  return 2;
	if (str=="three")  return 3;
	if (str=="four")  return 4;
	if (str=="five")  return 5;
	if (str=="six")  return 6;
	if (str=="seven")  return 7;
	if (str=="eight")  return 8;
	if (str=="nine")  return 9;
	return -1;
}


int main()
{
	vector<string>   vec1,vec2;
	vector<string>::iterator it;
     string   tmp1,tmp2;
	int A,B;
	while(true)
	{
		A=0;
        B=0;
		vec1.clear();
		vec2.clear();
		while(cin>>tmp1,tmp1!="+") vec1.push_back(tmp1);
		while(cin>>tmp2,tmp2!="=") vec2.push_back(tmp2);
		int len1 = vec1.size();
		int len2 = vec2.size();
        bool  flag = (*(vec1.begin())=="zero" && *(vec2.begin())=="zero" &&len1==1 &&len2==1);
	    if (flag)
	    break;
		for (int i=0;i<len1;i++)
		{
			A = A + getInt(vec1[i]) * (int)pow(10.0,(double)len1-1-i);
		}
		for (int i=0;i<len2;i++)
		{
			B = B + getInt(vec2[i]) * (int)pow(10.0,(double)len2-1-i);
		}
		cout<<A+B<<endl;

	}





	//system("pause");
	return 0;
}