/* * @lc app=leetcode.cn id=633 lang=java * * [633] 平方数之和 * * https://leetcode-cn.com/problems/sum-of-square-numbers/description/ * * algorithms * Easy (29.35%) * Total Accepted: 4K * Total Submissions: 13.6K * Testcase Example: '5' * * 给定一个非负整数 c ,你要判断是否存在两个整数 a 和 b,使得 a2 + b2 = c。 * * 示例1: * * * 输入: 5 * 输出: True * 解释: 1 * 1 + 2 * 2 = 5 * * * * * 示例2: * * * 输入: 3 * 输出: False * * */ class Solution { public boolean judgeSquareSum(int c) { boolean result = false; int half = c/2; for (int i =0;i*i<=half;i++) { int second = c-i*i; int temp = (int)Math.sqrt(second); if (temp*temp == second) { result = true; } } return result; } }