1129

题目链接：http://ifrog.cc/acm/problem/1129

思路就是用线段树查找最左边第一个大于等于v的数，然后返回线段树下表即可。

代码如下：

#include<bits/stdc++.h>
using namespace std;

struct node
{
    int l, r;
    long long x, add;
};

node tree[1000000 << 3];

void build(int l, int r, int k)
{
    tree[k].l = l, tree[k].r = r, tree[k].add = 0;
    if(l == r)
    {
        scanf("%lld", &tree[k].x);
        return ;
    }
    int mid = (l + r) >> 1;
    build(l, mid, k<<1);
    build(mid+1, r, k<<1|1);
    tree[k].x = max(tree[k<<1].x, tree[k<<1|1].x);
}

int query(int l, int r, int k, long long x)
{
    if(tree[k].l <= l && tree[k].r >= r)
    {
        if(tree[k].x < x)
            return -1;
    }

    if(tree[k].l == tree[k].r)
        return tree[k].l;

    if(tree[k].add)
    {
        tree[k<<1].x += tree[k].add, tree[k<<1|1].x += tree[k].add;
        tree[k<<1].add += tree[k].add, tree[k<<1|1].add += tree[k].add;
        tree[k].add = 0;
    }

    int res = -1;
    if(tree[k<<1].r >= l && tree[k<<1].x >= x)
        res = query(l, r, k<<1, x);
    if(res != -1)
        return res;
    if(tree[k<<1|1].l <= r && tree[k<<1|1].x >= x)
        res = query(l, r, k<<1|1, x);
    return res;
}

void updata(int l, int r, int k, long long x)
{
    if(tree[k].l >= l && tree[k].r <= r)
    {
        tree[k].x += x;
        tree[k].add += x;
        return ;
    }

    if(tree[k].add)
    {
        tree[k<<1].x += tree[k].add, tree[k<<1|1].x += tree[k].add;
        tree[k<<1].add += tree[k].add, tree[k<<1|1].add += tree[k].add;
        tree[k].add = 0;
    }

    if(tree[k<<1].r >= l)
        updata(l, r, k<<1, x);
    if(tree[k<<1|1].l <= r)
        updata(l, r, k<<1|1, x);

    tree[k].x = max(tree[k<<1].x, tree[k<<1|1].x);
}

void solve()
{
    int n, q;
    scanf("%d %d", &n, &q);
    build(1, n, 1);
    for(int i=0, op, l, r; i<q; ++ i)
    {
        long long v;
        scanf("%d %d %d %lld", &op, &l, &r, &v);
        if(op == 1)
            printf("%d
", query(l, r, 1, v));
        else
            updata(l, r, 1, v);
    }
}

int main()
{
    int t;
    scanf("%d", &t);
    while(t --)
        solve();
    return 0;
}