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  • 【341】Numpy 相关应用

    Numpy_01

    >>> from numpy import pi
    >>> np.linspace(0, 2, 9)
    array([0.  , 0.25, 0.5 , 0.75, 1.  , 1.25, 1.5 , 1.75, 2.  ])
    >>> x = np.linspace(0, 2*pi, 100)
    >>> y = np.sin(x)
    >>> import matplotlib.pyplot as plt
    >>> plt.plot(x, y, 'o')
    [<matplotlib.lines.Line2D object at 0x0000021025D65BA8>]
    >>> plt.show()
    

     

    Numpy_02

    >>> import numpy as np
    >>> import matplotlib.pyplot as plt
    >>> from numpy import pi
    >>> x = np.linspace(0, 2*pi, 100)
    >>> y1 = np.sin(x)
    >>> y2 = np.cos(x)
    >>> # sin
    >>> plt.plot(x, y1, 'g')
    [<matplotlib.lines.Line2D object at 0x000002C068E4C940>]
    >>> # cos
    >>> plt.plot(x, y2, 'r')
    [<matplotlib.lines.Line2D object at 0x000002C068E4CA90>]
    >>> # x = 0
    >>> y = np.linspace(-1, 1, 100)
    >>> plt.plot(x*0, y, 'b')
    [<matplotlib.lines.Line2D object at 0x000002C068E4CCF8>]
    >>> # x = 2*pi
    >>> plt.plot(x*0 + 2*pi, y, 'b')
    [<matplotlib.lines.Line2D object at 0x000002C068E4CD68>]
    >>> # y = 1
    >>> plt.plot(x, y*0 + 1, 'b')
    [<matplotlib.lines.Line2D object at 0x000002C05EEB4C50>]
    >>> # y = -1
    >>> plt.plot(x, y*0 - 1, 'b')
    [<matplotlib.lines.Line2D object at 0x000002C068E61E10>]
    >>> plt.show()
    

     

    Numpy_03

    >>> A = np.array([[1,1],
    		  [0,1]])
    >>> B = np.array([[2,0],
    		  [3,4]])
    >>> A * B        # 点乘,对应点的乘积
    array([[2, 0],
           [0, 4]])
    >>> A @ B        # 矩阵乘法
    array([[5, 4],
           [3, 4]])
    >>> A.dot(B)        # 矩阵乘法
    array([[5, 4],
           [3, 4]])
    >>> A * 2        # 乘以数字        
    array([[2, 2],
           [0, 2]])
    >>> A / 2        # 除以数字
    array([[0.5, 0.5],
           [0. , 0.5]])
    >>> A + B        # 矩阵加法
    array([[3, 1],
           [3, 5]])
    >>> A - B        # 矩阵减法
    array([[-1,  1],
           [-3, -3]])
    >>> B ** 2        # 对矩阵每个元素取平方
    array([[ 4,  0],
           [ 9, 16]], dtype=int32)    
    

     

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  • 原文地址:https://www.cnblogs.com/alex-bn-lee/p/10020409.html
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