Given a list of sorted characters letters
containing only lowercase letters, and given a target letter target
, find the smallest element in the list that is larger than the given target.
Letters also wrap around. For example, if the target is target = 'z'
and letters = ['a', 'b']
, the answer is 'a'
.
Examples:
Input: letters = ["c", "f", "j"] target = "a" Output: "c" Input: letters = ["c", "f", "j"] target = "c" Output: "f" Input: letters = ["c", "f", "j"] target = "d" Output: "f" Input: letters = ["c", "f", "j"] target = "g" Output: "j" Input: letters = ["c", "f", "j"] target = "j" Output: "c" Input: letters = ["c", "f", "j"] target = "k" Output: "c"
Note:
letters
has a length in range[2, 10000]
.letters
consists of lowercase letters, and contains at least 2 unique letters.target
is a lowercase letter.
1 class Solution { 2 public char nextGreatestLetter(char[] letters, char target) { 3 int low = 0, high = letters.length - 1; 4 char letter = '~'; 5 while (low <= high) { 6 int mid = low + (high - low) / 2; 7 if (letters[mid] > target) { 8 if (letters[mid] > target) { 9 letter = letters[mid]; 10 } 11 high = mid - 1; 12 } else { 13 low = mid + 1; 14 } 15 } 16 17 return letter == '~' ? letters[0] : letter; 18 } 19 }