zoukankan      html  css  js  c++  java
  • USACO Mixing Milk

    //很水的一题,用一次结构体排序就过了..

    Mixing Milk

    Since milk packaging is such a low margin business, it is important to keep the price of the raw product (milk) as low as possible. Help Merry Milk Makers get the milk they need in the cheapest possible manner.

    The Merry Milk Makers company has several farmers from which they may buy milk, and each one has a (potentially) different price at which they sell to the milk packing plant. Moreover, as a cow can only produce so much milk a day, the farmers only have so much milk to sell per day. Each day, Merry Milk Makers can purchase an integral amount of milk from each farmer, less than or equal to the farmer's limit.

    Given the Merry Milk Makers' daily requirement of milk, along with the cost per gallon and amount of available milk for each farmer, calculate the minimum amount of money that it takes to fulfill the Merry Milk Makers' requirements.

    Note: The total milk produced per day by the farmers will be sufficient to meet the demands of the Merry Milk Makers. 
    PROGRAM NAME: milk
    INPUT FORMAT

    Line 1: Two integers, N and M. 
    The first value, N, (0 <= N <= 2,000,000) is the amount of milk that Merry Milk Makers wants per day. The second, M, (0 <= M <= 5,000) is the number of farmers that they may buy from.
    Lines 2 through M+1: The next M lines each contain two integers, Pi and Ai. 
    Pi (0 <= Pi <= 1,000) is price in cents that farmer i charges.
    Ai (0 <= Ai <= 2,000,000) is the amount of milk that farmer i can sell to Merry Milk Makers per day.


    SAMPLE INPUT (file milk.in) 

    100 5  5 20  9 40  3 10  8 80  6 30  

    OUTPUT FORMAT

    A single line with a single integer that is the minimum price that Merry Milk Makers can get their milk at for one day. 
    SAMPLE OUTPUT (file milk.out)

    630  
    /*
    ID: jun41821
    PROG: milk
    LANG: C++
    */
    #include <iostream>
    #include <fstream>
    #include <algorithm>
    using namespace std;
    ofstream fout ("milk.out");
    ifstream fin ("milk.in");
    struct milk{
    int x;
    int y;
    }m[5002];
    int cmp(const void *a,const void *b)               //排序
    {
        struct milk *c=(milk*)a;
        struct milk *d=(milk*)b;
        return c->x-d->x;                   //对x排序
    }
    int main()
    {
        int i,N,M,sump=0,sumn=0;
        fin>>N>>M;                  //输入
        for(i=0;i<M;i++)
            fin>>m[i].x>>m[i].y;            //利用结构体排序
        //结构体排序
        qsort(m,M,sizeof(m[0]),cmp);
        for(i=0;i<M;i++)
            cout<<m[i].x<<' '<<m[i].y<<endl;            //利用结构体排序
        for(i=0;i<M&&sumn<=N;i++)
            if(sumn+m[i].y<=N)
            {
                sump+=m[i].x*m[i].y;
                sumn+=m[i].y;
            }
            else
            {
                sump+=m[i].x*(N-sumn);
                fout<<sump<<endl;
                return 0;
            }
            fout<<sump<<endl;
        return 0;
    }
  • 相关阅读:
    阻塞队列整理
    List与Map整理
    2、Redis中的链表
    【观点】从曾成杰案看民间金融的高风险与银行缺失的机制创新
    林权抵押贷款政策出台 将实现林业资源变资本
    从《男生传递微笑给女生的故事》想到的流程梳理与优化
    落实制度靠流程<摘自平安50万人的执行力>
    vue踩坑- 报错npm ERR! cb() never called!
    vue踩坑-This dependency was not found
    vue踩坑- 报错npm ERR! cb() never called!
  • 原文地址:https://www.cnblogs.com/amourjun/p/5134205.html
Copyright © 2011-2022 走看看