Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1 Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2 Output: False
Note:
- The input array won't violate no-adjacent-flowers rule.
- The input array size is in the range of [1, 20000].
- n is a non-negative integer which won't exceed the input array size.
Solution: use the greedy algorithm, plant flowers in each empty spot encountered from left to right without violating the rule.
1 class Solution { 2 public: 3 bool canPlaceFlowers(vector<int>& flowerbed, int n) { 4 flowerbed.insert(flowerbed.begin(),0); 5 flowerbed.push_back(0); 6 for(int i = 1; i < flowerbed.size()-1; ++i) 7 { 8 if(flowerbed[i-1] + flowerbed[i] + flowerbed[i+1] == 0) 9 { 10 --n; 11 ++i; 12 } 13 14 } 15 return n <=0; 16 } 17 };