一个线程可以,两个卡死
#!/usr/bin/python # coding: utf-8 from Tkinter import * import threading class MyThread2(threading.Thread): def __init__(self, func): threading.Thread.__init__(self) self.func = func def run(self): self.func() def windows1(): root = Tk() root.title("记事本") # root.geometry("800x600+100+100") s1 = Scrollbar(root) s1.pack(side=RIGHT, fill=Y) # HORIZONTAL 设置水平方向的滚动条,默认是竖直 s2 = Scrollbar(root, orient=HORIZONTAL) s2.pack(side=BOTTOM, fill=X) # 创建文本框 # wrap 设置不自动换行 textpad = Text(root, yscrollcommand=s1.set, xscrollcommand=s2.set, wrap='none') textpad.pack(expand=YES, fill=BOTH) s1.config(command=textpad.yview) s2.config(command=textpad.xview) root.mainloop() def windows2(): root = Tk() root.title("记事本") # root.geometry("800x600+100+100") s1 = Scrollbar(root) s1.pack(side=RIGHT, fill=Y) # HORIZONTAL 设置水平方向的滚动条,默认是竖直 s2 = Scrollbar(root, orient=HORIZONTAL) s2.pack(side=BOTTOM, fill=X) # 创建文本框 # wrap 设置不自动换行 textpad = Text(root, yscrollcommand=s1.set, xscrollcommand=s2.set, wrap='none') textpad.pack(expand=YES, fill=BOTH) s1.config(command=textpad.yview) s2.config(command=textpad.xview) root.mainloop() if __name__ == '__main__': threads = [] t1 = MyThread2(windows1) threads.append(t1) t2 = MyThread2(windows2) threads.append(t2) for t in threads: t.setDaemon(True) t.start() for t in threads: t.join()
运行一直等待中,不会出窗口
网上搜的结果,待验证。
tkinter和多线程确实有冲突,我也是弄了很久,最后才发现是这两者的问题。
后来我又自学了c#,发现其图形界面的控件是不允许多线程直接访问的,所以我推测python是因为图形下的控件被多线程同时访问(赋值),所以造成崩溃。
解决办法,我目前知道的(我是新手),要么不用多线程,要么不用tkinter。