前言
进入了日期章了。
年月日加减法
分别对原有的日期进行加减法。
sql server
select DATEADD(DAY,-5,HIREDATE) as hd_mimus_5D,
DATEADD(DAY,5,HIREDATE) as hd_plus_5D,
DATEADD(MONTH,-5,HIREDATE) as hd_minus_5M,
DATEDIFF(MONTH,5,HIREDATE) as hd_pulus_5M,
DATEADD(YEAR,-5,HIREDATE) as hd_minus_5Y,
DATEDIFF(YEAR,5,HIREDATE) as hd_pulus_5Y
from emp
where DEPTNO=20
mysql
select HIREDATE -INTERVAL 5 DAY as hd_mimus_5D,
HIREDATE + INTERVAL 5 DAY as hd_plus_5D,
HIREDATE -INTERVAL 5 MONTH as hd_minus_5M,
HIREDATE +INTERVAL 5 MONTH as hd_pulus_5M,
HIREDATE -INTERVAL 5 YEAR as hd_minus_5Y,
HIREDATE +INTERVAL 5 YEAR as hd_pulus_5Y
from emp
where DEPTNO=20
计算两个日期之间的天数
sql server 与 mysql
select DATEDIFF(DAY,word_hd,allen_hd)
from (
select HIREDATE as word_hd
from EMP
where ENAME='WARD'
)x,
(select HIREDATE as allen_hd
from EMP
where ENAME='ALLEN'
) y
在此只是为了介绍一下DATEDIFF函数可以计算两个日期的相差的间隔。
两个日期之间的工作日的天数
1.我们要知道两个日期区间是什么。比如说2月6号到2月23号,那么我们就要得出2月6号到2月23这个区间出来。
2.我们得出区间,那么我们需要遍历区间,然后判断那一天是工作日。
3.我们应该知道工作日是星期一到星期五。
mysql:
select sum(CASE when DATE_FORMAT(DATE_ADD(jones_hd,INTERVAL T100.ID-1 DAY),'%a') in ('Sat','Sun') then 0 else 1 END) as days
from
(select
MAX(case when ename='BLAKE' then HIREDATE end) as blake_hd,
MAX(case when ename='JONES' then HIREDATE end) as jones_hd
from EMP
where ename in ('BLAKE','JONES')
) x,T100
where T100.ID<=DATEDIFF(x.blake_hd,x.jones_hd)+1
看起来有一丢丢复杂,其实不然。
有两个地方你无需关注。
(select
MAX(case when ename='BLAKE' then HIREDATE end) as blake_hd,
MAX(case when ename='JONES' then HIREDATE end) as jones_hd
from EMP
where ename in ('BLAKE','JONES')
)
这一段仅仅是为了得出两个日期,也就是业务。其余部分才是功能。
如果你阅读了前面的章节,那么你仅仅需要关注的是DATE_FORMAT 函数。
sql server
select sum(CASE when
datename(DW,DATEADD(DAY,T100.ID-1,jones_hd)) in ('星期六','星期天') then 0 else 1 END) as days
from
(select
MAX(case when ename='BLAKE' then HIREDATE end) as blake_hd,
MAX(case when ename='JONES' then HIREDATE end) as jones_hd
from EMP
where ename in ('BLAKE','JONES')
) x,T100
where T100.ID<=DATEDIFF(DAY,x.jones_hd,x.blake_hd)+1
可能有人觉得我这里写星期六星期天奇怪哈,那是因为我自己的电脑装的是中文版。英文版是 in ('SATURDATA','SUNDAY')。
知识点:datename函数
计算两个日期之间相差的月份和年份
mysql:
select x.mounths as ms,x.mounths/12 as ys from
(select ((YEAR(max_hir)-YEAR(min_hir))*12+(MONTH(max_hir)-MONTH(min_hir))) as mounths from
(select MIN(HIREDATE) as min_hir,MAX(HIREDATE) AS max_hir
FROM EMP) e
)x
sql server
select DATEDIFF(MONTH,e.min_hir,e.max_hir) as ms,CAST(DATEDIFF(MONTH,e.max_hir,e.min_hir) as decimal )/12 from
(select MIN(HIREDATE) as min_hir,MAX(HIREDATE) AS max_hir
FROM EMP
) e
注:在做除法的时候一定要转换一下数据类型。
计算两个日期之间相差的秒数、分钟数、小时数
mysql 和 sqlserver 通用
select DATEDIFF(day,e.min_hir,e.max_hir)*12 as hrs,DATEDIFF(day,e.min_hir,e.max_hir)*12*60 as mins,DATEDIFF(day,e.min_hir,e.max_hir)*12*60*60 as sec from
(select MIN(HIREDATE) as min_hir,MAX(HIREDATE) AS max_hir
FROM EMP
) e