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  • Number of Boomerangs

    Given n points in the plane that are all pairwise distinct, a "boomerang" is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k (the order of the tuple matters).

    Find the number of boomerangs. You may assume that n will be at most 500 and coordinates of points are all in the range [-10000, 10000] (inclusive).

    Example:
    Input:
    [[0,0],[1,0],[2,0]]

    Output:

    Explanation:
    The two boomerangs are [[1,0],[0,0],[2,0]] and [[1,0],[2,0],[0,0]]

    public int numberOfBoomerangs(int[][] points) {
        int res = 0;
    
        Map<Integer, Integer> map = new HashMap<>();
        for(int i=0; i<points.length; i++) {
            for(int j=0; j<points.length; j++) {
                if(i == j)
                    continue;
                
                int d = getDistance(points[i], points[j]);                
                map.put(d, map.getOrDefault(d, 0) + 1);
            }
            
            for(int val : map.values()) {
                res += val * (val-1);
            }            
            map.clear();
        }
        
        return res;
    }
    
    private int getDistance(int[] a, int[] b) {
        int dx = a[0] - b[0];
        int dy = a[1] - b[1];
        
        return dx*dx + dy*dy;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/apanda009/p/7789107.html
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