zoukankan      html  css  js  c++  java
  • 32. Longest Valid Parentheses

    Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring.

    For "(()", the longest valid parentheses substring is "()", which has length = 2.

    Another example is ")()())", where the longest valid parentheses substring is "()()", which has length = 4.

    The workflow of the solution is as below.

      1. Scan the string from beginning to end.
      2. If current character is '(',
        push its index to the stack. If current character is ')' and the
        character at the index of the top of stack is '(', we just find a
        matching pair so pop from the stack. Otherwise, we push the index of
        ')' to the stack.
      3. After the scan is done, the stack will only
        contain the indices of characters which cannot be matched. Then
        let's use the opposite side - substring between adjacent indices
        should be valid parentheses.
      4. If the stack is empty, the whole input
        string is valid. Otherwise, we can scan the stack to get longest
        valid substring as described in step 3.
    class Solution {
    public:
        int longestValidParentheses(string s) {
            int n = s.length(), longest = 0;
            stack<int> st;
            for (int i = 0; i < n; i++) {
                if (s[i] == '(') st.push(i);
                else {
                    if (!st.empty()) {
                        if (s[st.top()] == '(') st.pop();
                        else st.push(i);
                    }
                    else st.push(i);
                }
            }
            if (st.empty()) longest = n;
            else {
                int a = n, b = 0;
                while (!st.empty()) {
                    b = st.top(); st.pop();
                    longest = max(longest, a-b-1);
                    a = b;
                }
                longest = max(longest, a);
            }
            return longest;
        }
    };
    

      

  • 相关阅读:
    MySQL数据库之索引
    python面向对象编程
    linux端口占用
    lintcode
    java基础
    lintcode
    linux 常用命令
    Docker & Kubernates
    angular preparation
    java 命令行
  • 原文地址:https://www.cnblogs.com/apanda009/p/7807563.html
Copyright © 2011-2022 走看看