好久没用Struts了，今天练了一个简单的应用，出现了一些意外的问题，由于这种原因一直报404
首先我的目录结构是这样子滴
web.xml中是这样配置的
<web-app>
<display-name>Archetype Created Web Application</display-name>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>/WEB-INF/welcome.jsp</welcome-file>
</welcome-file-list>
</web-app>
很简单，struts拦截所有，外加一个欢迎页
struts.xml是这样的
<struts>
<constant name="struts.devMode" value="true"></constant>
<constant name="struts.i18n.encoding" value="UTF-8"></constant>
<constant name="struts.locale" value="zh_CN"></constant>
<package name="default" namespace="/WEB-INF/pages" extends="struts-default">
<action name="index">
<result>login.jsp</result>
</action>
<action name="login" class="com.tjjy.struts.Login">
<result name="SUCCESS">ok.jsp</result>
</action>
</package>
</struts>
这里只有一个命名空间
欢迎页配置更简单
<body>
欢迎！！！！！！！！！！！！！！！
<a href = "index.action">点我</a>
</body>
思路是：启动服务器，首先进入欢迎页然后进去登陆页，然后登陆成功
但运行时却是
There is no Action mapped for namespace [/] and action name [] associated with context path [/StrutsTest]. - [unknown location]
at com.opensymphony.xwork2.DefaultActionProxy.prepare(DefaultActionProxy.java:185)
at org.apache.struts2.impl.StrutsActionProxy.prepare(StrutsActionProxy.java:63)
at org.apache.struts2.impl.StrutsActionProxyFactory.createActionProxy(StrutsActionProxyFactory.java:39)
at com.opensymphony.xwork2.DefaultActionProxyFactory.createActionProxy(DefaultActionProxyFactory.java:58)
at org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:536)
at org.apache.struts2.dispatcher.ng.ExecuteOperations.executeAction(ExecuteOperations.java:77)
at org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter.doFilter(StrutsPrepareAndExecuteFilter.java:91)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:220)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:122)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:503)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:170)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:103)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:950)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:116)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:421)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1070)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:611)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:314)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.lang.Thread.run(Thread.java:744)
说我的该命名空间下找不到我要请求的action
一开始以为struts拦截器有问题分别进行修改
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.action</url-pattern>
</filter-mapping>
<package name="default" namespace="/WEB-INF/pages" extends="struts-default">
<action name="index.action">
<result>login.jsp</result>
</action>
结果依然和上面一样，很明显问题不在这里，但明明报错是说找不到action，那就一定是url的问题，后经过一段时间，进行各种url写法的尝试，都失败了，换个角度是不是在欢迎页就开始出问题了
这下发现一个很愚蠢很低级的问题就是，欢迎页的路径错误，改为：
<welcome-file-list>
<welcome-file>/WEB-INF/welcome.jsp</welcome-file>
</welcome-file-list>
成功，又试了上面的更改过的url方式，都是没问题的，知识不能一味追求新的，要温故而知新，时间久不用竟然连基础的都忘了