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  • 149. Max Points on a Line *HARD* 求点集中在一条直线上的最多点数

    Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.

    /**
     * Definition for a point.
     * struct Point {
     *     int x;
     *     int y;
     *     Point() : x(0), y(0) {}
     *     Point(int a, int b) : x(a), y(b) {}
     * };
     */
    class Solution {
    public:
        int maxPoints(vector<Point>& points) {
            int n = points.size(), i, j, ans = 0;
            if(1 == n)
                return 1;
            for(i = 0; i < n; i++)
            {
                map<double, int> m;
                map<int, int> x, y;
                int samePoint = 0;
                for(j = 0; j < n; j++)
                {
                    int deltaX = points[i].x - points[j].x;
                    int deltaY = points[i].y - points[j].y;
                    if(0 == deltaX && 0 == deltaY)
                    {
                        samePoint++;
                    }
                    else if(0 == deltaX)
                    {
                        if(x.find(points[i].x) == x.end())
                            x[points[i].x] = 1;
                        else
                            x[points[i].x]++;
                    }
                    else if(0 == deltaY)
                    {
                        if(y.find(points[i].y) == y.end())
                            y[points[i].y] = 1;
                        else
                            y[points[i].y]++;
                    }
                    else
                    {
                        double t = 1.0 * deltaX / deltaY;
                        if(m.find(t) == m.end())
                            m[t] = 1;
                        else
                            m[t]++;
                    }
                }
                ans = max(ans, samePoint);
                for(map<double, int>::iterator it = m.begin(); it != m.end(); it++)
                    ans = max(ans, it->second+samePoint);
                for(map<int, int>::iterator it = x.begin(); it != x.end(); it++)
                    ans = max(ans, it->second+samePoint);
                for(map<int, int>::iterator it = y.begin(); it != y.end(); it++)
                    ans = max(ans, it->second+samePoint);
            }
            return ans;
        }
    };
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  • 原文地址:https://www.cnblogs.com/argenbarbie/p/5791330.html
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