是这样的……
今天我考试的时候，闲的无聊，就开始写一串无聊代码
1 #include<cstdio> 2 using namespace std; 3 int main() 4 { 5 freopen("1.in","r",stdin); 6 freopen("1.out","w",stdout); 7 #include<cstdio> 8 using namespace std; 9 int main() 10 { 11 freopen("2.in","r",stdin); 12 freopen("2.out","w",stdout); 13 return 2; 14 } 15 return 1; 16 }
就是这个一个套一个的程序……后来层数越来越多了，觉得手打太累，就写了一个小程序帮我输出这玩意
1 #include<cstdio> 2 using namespace std; 3 int m; 4 void pk(int n) 5 { 6 if(n == 0) return; 7 for(int i = 1;i <= n;i++) printf(" "); 8 } 9 void p(int n) 10 { 11 if(n == m + 1) return; 12 pk(n - 1); 13 printf("#include<cstdio> "); 14 pk(n - 1); 15 printf("using namespace std; "); 16 pk(n - 1); 17 printf("int main() "); 18 pk(n - 1); 19 printf("{ "); 20 pk(n); 21 printf("freopen(""); 22 printf("%d",n); 23 printf(".in","r",stdin); "); 24 pk(n); 25 printf("freopen(""); 26 printf("%d",n); 27 printf(".out","w",stdout); "); 28 p(n + 1); 29 pk(n); 30 printf("return "); 31 printf("%d",n); 32 printf("; "); 33 pk(n - 1); 34 printf("} "); 35 } 36 int main() 37 { 38 freopen("hhh.out","w",stdout); 39 scanf("%d",&m); 40 p(1); 41 return 0; 42 }
相信有点c艹基础的人都能看懂
这是输入n = 5的结果
1 #include<cstdio> 2 using namespace std; 3 int main() 4 { 5 freopen("1.in","r",stdin); 6 freopen("1.out","w",stdout); 7 #include<cstdio> 8 using namespace std; 9 int main() 10 { 11 freopen("2.in","r",stdin); 12 freopen("2.out","w",stdout); 13 #include<cstdio> 14 using namespace std; 15 int main() 16 { 17 freopen("3.in","r",stdin); 18 freopen("3.out","w",stdout); 19 #include<cstdio> 20 using namespace std; 21 int main() 22 { 23 freopen("4.in","r",stdin); 24 freopen("4.out","w",stdout); 25 #include<cstdio> 26 using namespace std; 27 int main() 28 { 29 freopen("5.in","r",stdin); 30 freopen("5.out","w",stdout); 31 return 5; 32 } 33 return 4; 34 } 35 return 3; 36 } 37 return 2; 38 } 39 return 1; 40 }
然后我又试了一下n = 100……
这个建议自己试一下