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  • 用jQuery判断两个元素是否有重叠部分

      这是博问中的一个问题:http://q.cnblogs.com/q/39172/

      我的方案如下:

    function isOverlap(idOne,idTwo){
        var objOne=$("#"+idOne),
            objTwo=$("#"+idTwo),
            offsetOne = objOne.offset(),
            offsetTwo = objTwo.offset(),
            topOne=offsetOne.top,
            topTwo=offsetTwo.top,
            leftOne=offsetOne.left,
            leftTwo=offsetTwo.left,
            widthOne = objOne.width(),
            widthTwo = objTwo.width(),
            heightOne = objOne.height(),
            heightTwo = objTwo.height();
        var leftTop = leftTwo > leftOne && leftTwo < leftOne+widthOne 
                && topTwo > topOne && topTwo < topOne+heightOne,
            rightTop = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne 
                && topTwo > topOne && topTwo < topOne+heightOne,
            leftBottom = leftTwo > leftOne && leftTwo < leftOne+widthOne 
                && topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne,
            rightBottom = leftTwo+widthTwo > leftOne && leftTwo+widthTwo < leftOne+widthOne 
                && topTwo+heightTwo > topOne && topTwo+heightTwo < topOne+heightOne;
        return leftTop || rightTop || leftBottom || rightBottom;
    }

      原理很简单,就是判断一个元素的四个点是否在另一个元素内部。

      Demo:

      如果有其他方案欢迎提出。

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  • 原文地址:https://www.cnblogs.com/artwl/p/2607922.html
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