leetcode53

public class Solution {
    public int MaxSubArray(int[] nums) {
        int max = int.MinValue;
            int sum = 0;
            for (int i = 0; i < nums.Length; i++)
            {
                if (sum < 0)
                {
                    sum = nums[i];
                }
                else
                {
                    sum += nums[i];
                }
                if (sum > max)
                {
                    max = sum;
                }
            }
            return max;
    }
}

https://leetcode.com/problems/maximum-subarray/#/description

补充一个python的实现：

import sys
class Solution:
    def maxSubArray(self, nums: 'List[int]') -> 'int':
        sums = 0
        maxsum = -sys.maxsize
        n = len(nums)
        for i in range(n):
            if sums < 0:
                sums = nums[i]
                maxsum = max(maxsum,nums[i])#使用当前值更新最大值
            else:
                sums += nums[i]
                maxsum = max(maxsum,sums)#使用当前连续和更新最大值
        return maxsum

算法思路：贪心法。