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  • leetcode524

    public class Solution {
        public string FindLongestWord(string s, IList<string> d) {
            string longest = "";
                foreach (var dictWord in d)
                {
                    int i = 0;
                    foreach (var c in s)
                    {
                        if (i < dictWord.Length && c == dictWord[i])
                        {
                            i++;
                        }
                    }
    
                    if (i == dictWord.Length && dictWord.Length >= longest.Length)
                    {
                        if (dictWord.Length > longest.Length || dictWord.CompareTo(longest) < 0)
                        {
                            longest = dictWord;
                        }
                    }
                }
                return longest;
        }
    }

    https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/#/description

    补充一个python的实现:

     1 class Solution:
     2     def findLongestWord(self, s: str, d: 'List[str]') -> str:
     3         maxlen = 0
     4         longestword = ''
     5         for sd in d:            
     6             curlen = 0
     7             i=0
     8             j=0
     9             while i<len(s) and j<len(sd):
    10                 if s[i]==sd[j]:
    11                     curlen += 1
    12                     if curlen == len(sd):
    13                         if curlen > maxlen or (curlen == maxlen and sd<longestword):
    14                             maxlen = curlen
    15                             longestword = sd
    16 
    17                         break
    18                     else:
    19                         i+=1
    20                         j+=1
    21                 else:
    22                     i+=1
    23         return longestword

    再补充一个java实现:

     1 class Solution {
     2     public String findLongestWord(String s, List<String> d) {
     3         String longestWord = "";
     4         for (String target : d) {
     5             int l1 = longestWord.length(), l2 = target.length();
     6             if (l1 > l2 || (l1 == l2 && longestWord.compareTo(target) < 0)) {
     7                 continue;
     8             }
     9             if (isSubstr(s, target)) {
    10                 longestWord = target;
    11             }
    12         }
    13         return longestWord;
    14     }
    15 
    16     private boolean isSubstr(String s, String target) {
    17         int i = 0, j = 0;
    18         while (i < s.length() && j < target.length()) {
    19             if (s.charAt(i) == target.charAt(j)) {
    20                 j++;
    21             }
    22             i++;
    23         }
    24         return j == target.length();
    25     }
    26 }
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  • 原文地址:https://www.cnblogs.com/asenyang/p/6939632.html
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