原题: https://www.patest.cn/contests/pat-b-practise/1066
思路: 开胃小菜
实现:
#include <stdio.h>
int main (void) {
int m;
int n;
int a;
int b;
int c;
char ch;
int tmp;
int i;
int j;
scanf("%d %d %d %d %d", &m, &n, &a, &b, &c);
// 题目说了这么多就是一句话, 如果tmp在[a, b]打印c否则打印tmp
for (i = 1; i <= m; i++) {
ch = ' ';
for (j = 1; j <= n; j++) {
if (j == n) ch = '
';
scanf("%d", &tmp);
if (tmp >= a && tmp <= b) {
printf("%03d%c", c, ch);
} else {
printf("%03d%c", tmp, ch);
}
}
}
return 0;
}