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  • hdu 4401 Battery

    这里只给出代码,感兴趣的可以作以参考:

    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    #include <string>
    #include <queue>
    #include <map>
    #include <set>
    #include <stack>
    #include <ctime>
    #include <functional>
    #include <cmath>
    #include <iostream>
    #include <assert.h>
    #pragma comment(linker, "/STACK:102400000,102400000")
    #define max(a, b) ((a) > (b) ? (a) : (b))
    #define min(a, b) ((a) < (b) ? (a) : (b))
    #define mp std :: make_pair
    #define st first
    #define nd second
    #define keyn (root->ch[1]->ch[0])
    #define lson (u << 1)
    #define rson (u << 1 | 1)
    #define pii std :: pair<int, int>
    #define pll pair<ll, ll>
    #define pb push_back
    #define type(x) __typeof(x.begin())
    #define foreach(i, j) for(type(j)i = j.begin(); i != j.end(); i++)
    #define FOR(i, s, t) for(int i = (s); i <= (t); i++)
    #define ROF(i, t, s) for(int i = (t); i >= (s); i--)
    #define dbg(x) std::cout << x << std::endl
    #define dbg2(x, y) std::cout << x << " " << y << std::endl
    #define clr(x, i) memset(x, (i), sizeof(x))
    #define maximize(x, y) x = max((x), (y))
    #define minimize(x, y) x = min((x), (y))
    using namespace std;
    typedef long long ll;
    const int int_inf = 0x3f3f3f3f;
    const ll ll_inf = 0x3f3f3f3f3f3f3f3f;
    const int INT_INF = (int)((1ll << 31) - 1);
    const double double_inf = 1e30;
    const double eps = 1e-14;
    const double pi = acos(-1.);
    typedef unsigned long long ul;
    typedef unsigned int ui;
    inline int readint() {
        int x;
        scanf("%d", &x);
        return x;
    }
    inline int readstr(char *s) {
        scanf("%s", s);
        return strlen(s);
    }
    
    class cmpt {
    public:
        bool operator () (const int &x, const int &y) const {
            return x > y;
        }
    };
    
    int Rand(int x, int o) {
        //if o set, return [1, x], else return [0, x - 1]
        if (!x) return 0;
        int tem = (int)((double)rand() / RAND_MAX * x) % x;
        return o ? tem + 1 : tem;
    }
    ll ll_rand(ll x, int o) {
        if (!x) return 0;
        ll tem = (ll)((double)rand() / RAND_MAX * x) % x;
        return o ? tem + 1 : tem;
    }
    
    void data_gen() {
        srand(time(0));
        freopen("in.txt", "w", stdout);
        int kases = 100;
        //printf("%d
    ", kases);
        while (kases--) {
            int L = Rand(1000, 1) + 5;
            int n = Rand(L - 4, 1) + 3;
            int buf[1500], p = 0;
            FOR(i, 1, n) buf[i] = Rand(L, 0);
            buf[++n] = 0, buf[++n] = L;
            sort(buf + 1, buf + n + 1);
            n = unique(buf + 1, buf + n + 1) - buf - 1;
            printf("%d %d
    ", L, n);
            int t1 = Rand(13, 0) + 6;
            int t2 = Rand(13, 0) + 6;
            while (t2 == t1) {
                t2 = Rand(13, 0) + 6;
            }
            if (t1 > t2) swap(t1, t2);
            printf("%d %d
    ", t1, t2);
            FOR(i, 1, n) {
                printf("%d %d
    ", buf[i], Rand(1000, 1));
            }
            puts("
    ");
        }
        puts("0 0");
    }
    
    const int maxn = 1e3 + 10;
    pii a[maxn];
    int n, L;
    int t1, t2;
    struct Line {
        int lhs, rhs;
        double theta;
        int o;
        Line() {}
        Line(int _lhs, int _rhs, double _ta, int _o) {
            lhs = _lhs, rhs = _rhs, theta = _ta, o = _o;
        }
        bool operator < (const Line &other) {
            return theta > other.theta || theta == other.theta && rhs > other.rhs ||
                theta == other.theta && rhs == other.rhs && lhs > other.lhs;
        }
    }lines[maxn * maxn];
    int k;
    double shadow, H;
    bool inq[maxn];
    
    double cal(double theta1, double theta2) {
        if (abs(theta1 - theta2) < eps) return 0;
        double X = abs(theta1 - pi / 2) < eps ? 0 : H / tan(theta1);
        double ret = (cos(theta2) - cos(theta1)) * (L - shadow + X) - H * (sin(theta1) - sin(theta2));
        shadow += abs(theta2) < eps ? L - shadow : H / tan(theta2) - X;
        return ret;
    }
    
    double solve(int l, int r) {
        shadow = H = 0;
        k = 0;
        FOR(i, 2, n) {
            inq[i] = 1;
            H += a[i].nd;
            double mini = (double)ll_inf;
            int mk = 0;
            ROF(j, i - 1, 1) {
                double ang_tan = (double)a[i].second / (a[i].first - a[j].first);
                lines[k++] = Line(j, i, atan(ang_tan), 0);
                if (a[i].second <= a[j].second) break;
                ang_tan = (double)(a[i].second - a[j].second) / (a[i].first - a[j].first);
                lines[k++] = Line(j, i, atan(ang_tan), 1);
            }
        }
        double ang_l = pi / 12 * (18 - l), ang_r = pi / 12 * (18 - r);
        lines[k++] = Line(0, 0, ang_l, 2), lines[k++] = Line(0, 0, ang_r, 3);
        sort(lines, lines + k);
        double ans = 0;
        bool okay = false;
        double pre = pi / 2;
        FOR(i, 0, k - 1) {
            int o = lines[i].o;
            int lhs = lines[i].lhs, rhs = lines[i].rhs;
            double ang = lines[i].theta;
            double res = cal(pre, ang);
            if (okay) ans += res;
            if (o == 3) break;
            else if (o == 2) okay = true;
            else if (o == 0 && inq[rhs]) inq[rhs] = 0, H -= a[rhs].nd, mk = 1;
            else if (o == 1 && inq[lhs]) H += a[rhs].nd - a[lhs].nd, inq[lhs] = 0, inq[rhs] = 1, mk = 1;
            pre = ang;
        }
        return abs(ans * 12 / pi);
    }
    
    int main() {
        //data_gen(); return 0;
        //C(); return 0;
        int debug = 0;
        if (debug) freopen("in.txt", "r", stdin);
        //freopen("out.txt", "w", stdout);
        int kases = 0;
        while (~scanf("%d%d", &L, &n) && n) {
            ++kases;
            t1 = readint(), t2 = readint();
            FOR(i, 1, n) scanf("%d%d", &a[i].st, &a[i].nd);
            double ans = 0;
            if (t1 >= 12) ans += solve(t1, t2);
            else {
                if (t2 > 12) ans += solve(12, t2), t2 = 12;
                FOR(i, 1, n) a[i].first = L - a[i].st;
                FOR(i, 1, n / 2) swap(a[i], a[n + 1 - i]);
                ans += solve(24 - t2, 24 - t1);
            }
            printf("%.5f
    ", ans);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/astoninfer/p/5951389.html
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