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  • 127. Word Ladder

    class Solution {
        public int ladderLength(String beginWord, String endWord, List<String> wordList) {
            Set<String> dict=new HashSet<String>(wordList);
            if(!dict.contains(endWord))
                return 0;
            Set<String> set1=new HashSet<String>(Arrays.asList(beginWord));
            Set<String> set2=new HashSet<String>(Arrays.asList(endWord));
            return ladderLength(set1, set2, dict, 1);
        }
        private int ladderLength(Set<String> set1, Set<String> set2, Set<String> dict, int level) {
            if(set1.size()==0)
                return 0;
            if(set1.size()>set2.size())
                return ladderLength(set2, set1, dict, level);
            dict.removeAll(set1);
            dict.removeAll(set2);
            Set<String> set3=new HashSet<String>();
            for(String w:set1)
                for(int i=0;i<w.length();i++)
                {
                    char[] arr=w.toCharArray();
                    for(char ch='a';ch<='z';ch++)
                    {
                        arr[i]=ch;
                        String word=new String(arr);
                        if(set2.contains(word))
                            return level+1;
                        if(dict.contains(word))
                            set3.add(word);
                    }
                }
            return ladderLength(set2, set3, dict, level+1);
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/asuran/p/7624960.html
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