实验8：Problem F: 让动物们叫起来吧！

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Problem F: 让动物们叫起来吧！

Problem F: 让动物们叫起来吧！

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 420  Solved: 331
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Description

Tom家里养了很多动物，比如有鸭子、火鸡和公鸡。它们的叫声都不相同。现在，请编写类Animal、Cock、Turkey和Duck，根据给出的main()函数及样例分析每个类的属性、行为及相互关系，以模仿Tom家的情况。

提示：动物们都有自己的名字。

Input

输入有多行。第一行正整数M表示之后有M个测试用例，每个测试用例包括2部分：前一部分是动物的名字，后一部分是动物的类型（用A、B、C分别表示鸭子、火鸡和公鸡）。

Output

输出有M行，每个测试用例对应一样。见样例。

Sample Input

3 Baby C Rubby B Tobby A

Sample Output

Baby is a cock, and it can crow. Rubby is a turkey, and it can gobble. Tobby is a duck, and it can quack.

HINT

 

Append Code

append.cc,

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#include<iostream>
using namespace std;
class Animal{
protected:

string n;

public:
    Animal(){}
    Animal(string name):n(name){}
    void sound(){}
};
class Cock:public Animal{
protected:
    string n;
public:
    Cock(string name):n(name){cout<<n<<" is a cock, and it can crow."<<endl;}
    void sound(){cout<<n<<" is a cock, and it can crow."<<endl;}
};
class Turkey:public Animal{
protected:
    string n;
public:
    Turkey(string name):n(name){cout<<n<<" is a turkey, and it can gobble."<<endl;}
    void sound(){cout<<n<<" is a turkey, and it can gobble."<<endl;}

};
class Duck:public Animal{
protected:
    string n;
public:
    Duck(string name):n(name){cout<<n<<" is a duck, and it can quack."<<endl;}
    void sound(){cout<<n<<" is a duck, and it can quack."<<endl;}
};

int main()
{
    int cases;
    string name;
    char type;
    Animal *animal;
    cin>>cases;
    for (int i = 0; i < cases; i++)
    {
       cin>>name>>type;
       switch(type)
       {
        case 'A':
            animal = new Duck(name);
            break;
        case 'B':
            animal = new Turkey(name);
            break;
        case 'C':
            animal = new Cock(name);
            break;
       }
       animal->sound();
    }
    return 0;
}