Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
public class Solution { /**There is not special algorithm for this problem.<br> * 1. sort the intervals according to the start point * 2. linear scan the sorted intervals and then merge them together * * @param intervals --List of Intervals. * @return --List of Intervals, in which no intervals have overlaps * @author Averill Zheng * @version 2014-06-12--world cup opening day * @since JDK 1.7 */ public List<Interval> merge(List<Interval> intervals) { List<Interval> result = new ArrayList<Interval>(); if(!intervals.isEmpty()){ Collections.sort(intervals, new IntervalComparator()); int length = intervals.size(); int start = intervals.get(0).start; int end = intervals.get(0).end; for(int i = 1; i < length; ++i){ Interval current = intervals.get(i); if(current.start <= end) end = Math.max(end, current.end); else{ result.add(new Interval(start, end)); start = current.start; end = current.end; } } result.add(new Interval(start, end)); } return result; } } class IntervalComparator implements Comparator<Interval>{ public int compare(Interval a, Interval b){ return Integer.compare(a.start, b.start); } }