///分苹果给两个人 判断是否能够平分 苹果不能切，存在200g和100g的苹果
我每次想这种题目都会绕很远 so sad cf上的题目果然每次都让我很暴躁啊
Description
Kitahara Haruki has bought n apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't want to offend any of his friend. Therefore the total weight of the apples given to Touma Kazusa must be equal to the total weight of the apples given to Ogiso Setsuna.
But unfortunately Kitahara Haruki doesn't have a knife right now, so he cannot split any apple into some parts. Please, tell him: is it possible to divide all the apples in a fair way between his friends?
Input
The first line contains an integer n(1 ≤ n ≤ 100) — the number of apples. The second line contains n integers w1, w2, ..., wn (wi = 100 or wi = 200), where wi is the weight of the i-th apple.
Output
In a single line print "YES" (without the quotes) if it is possible to divide all the apples between his friends. Otherwise print "NO" (without the quotes).
Sample Input
Input
3
100 200 100
Output
YES
Input
4
100 100 100 200
Output
NO
Hint
In the first test sample Kitahara Haruki can give the first and the last apple to Ogiso Setsuna and the middle apple to Touma Kazusa.
1 #include<stdio.h> 2 3 int main() 4 5 { 6 7 int n,i,a[100]; 8 9 while(~scanf("%d",&n)) 10 11 { 12 13 int ans=0; 14 15 int temp; 16 17 for(i=0;i<n;i++) 18 19 { 20 21 scanf("%d",&a[i]); 22 23 if(a[i]==200) 24 25 ans++; 26 27 } 28 29 temp=n-ans; 30 31 if(temp==0&&ans%2!=0) 32 33 puts("NO"); 34 35 else if(temp%2==0&&n!=1) 36 37 puts("YES"); 38 39 else 40 41 puts("NO"); 42 43 } 44 45 return 0; 46 47 }