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  • Unique Paths

    A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).

    The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).

    How many possible unique paths are there?

    Above is a 3 x 7 grid. How many possible unique paths are there?

    Note: m and n will be at most 100.

    思路:本题意思是通过向下走或者向右走到达Finish,我们可以抽象一下,到达(i,j)点必通过(i-1,j)或者(i,j-1).所以使用result[i][j]表示到达(i,j)有多少中方法,故result[i][j]=result[i-1][j]+result[i][j-1];

    class Solution {
    public:
        int uniquePaths(int m, int n) {
            int result[m][n];
            for(int i=0;i<m;i++)
                result[i][0]=1;
            for(int j=0;j<n;j++)
                result[0][j]=1;
            for(int i=1;i<m;i++)
            {
                for(int j=1;j<n;j++)
                {
                    result[i][j]=result[i-1][j]+result[i][j-1];
                }
            }
            return result[m-1][n-1];
        }
    };
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  • 原文地址:https://www.cnblogs.com/awy-blog/p/3618404.html
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