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  • .net金额转大写

    如果会写但又要节省时间,你只要用这个方法就可以得到,金额的大写转换,祝你好运.  ,这里有两种发放,都是从网络上找的,我在这里总结一下。

    //金额转大写

    第一种方法       

       public static string chang1(decimal num)
            {
                string str1 = "零壹贰叁肆伍陆柒捌玖";            //0-9所对应的汉字
                string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
                string str3 = "";    //从原num值中取出的值
                string str4 = "";    //数字的字符串形式
                string str5 = "";  //人民币大写金额形式
                int i;    //循环变量
                int j;    //num的值乘以100的字符串长度
                string ch1 = "";    //数字的汉语读法
                string ch2 = "";    //数字位的汉字读法
                int nzero = 0;  //用来计算连续的零值是几个
                int temp;            //从原num值中取出的值

                num = Math.Round(Math.Abs(num), 2);    //将num取绝对值并四舍五入取2位小数
                str4 = ((long)(num * 100)).ToString();        //将num乘100并转换成字符串形式
                j = str4.Length;      //找出最高位
                if (j > 15) { return "溢出"; }
                str2 = str2.Substring(15 - j);   //取出对应位数的str2的值。如:200.55,j为5所以tr2=佰拾元角分

                //循环取出每一位需要转换的值
                for (i = 0; i < j; i++)
                {
                    str3 = str4.Substring(i, 1);          //取出需转换的某一位的值
                    temp = Convert.ToInt32(str3);      //转换为数字
                    if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
                    {
                        //当所取位数不为元、万、亿、万亿上的数字时
                        if (str3 == "0")
                        {
                            ch1 = "";
                            ch2 = "";
                            nzero = nzero + 1;
                        }
                        else
                        {
                            if (str3 != "0" && nzero != 0)
                            {
                                ch1 = "零" + str1.Substring(temp * 1, 1);
                                ch2 = str2.Substring(i, 1);
                                nzero = 0;
                            }
                            else
                            {
                                ch1 = str1.Substring(temp * 1, 1);
                                ch2 = str2.Substring(i, 1);
                                nzero = 0;
                            }
                        }
                    }
                    else
                    {
                        //该位是万亿,亿,万,元位等关键位
                        if (str3 != "0" && nzero != 0)
                        {
                            ch1 = "零" + str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                        else
                        {
                            if (str3 != "0" && nzero == 0)
                            {
                                ch1 = str1.Substring(temp * 1, 1);
                                ch2 = str2.Substring(i, 1);
                                nzero = 0;
                            }
                            else
                            {
                                if (str3 == "0" && nzero >= 3)
                                {
                                    ch1 = "";
                                    ch2 = "";
                                    nzero = nzero + 1;
                                }
                                else
                                {
                                    if (j >= 11)
                                    {
                                        ch1 = "";
                                        nzero = nzero + 1;
                                    }
                                    else
                                    {
                                        ch1 = "";
                                        ch2 = str2.Substring(i, 1);
                                        nzero = nzero + 1;
                                    }
                                }
                            }
                        }
                    }
                    if (i == (j - 11) || i == (j - 3))
                    {
                        //如果该位是亿位或元位,则必须写上
                        ch2 = str2.Substring(i, 1);
                    }
                    str5 = str5 + ch1 + ch2;

                    if (i == j - 1 && str3 == "0")
                    {
                        //最后一位(分)为0时,加上“整”
                        str5 = str5 + '整';
                    }
                }
                if (num == 0)
                {
                    str5 = "零元整";
                }
                return str5;
            }

    第二种方法

    public string chang2(string money)
            {
                //将小写金额转换成大写金额          
                double MyNumber = Convert.ToDouble(money);
                String[] MyScale = { "分", "角", "元", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "兆", "拾", "佰", "仟" };
                String[] MyBase = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };
                String M = "";
                bool isPoint = false;
                if (money.IndexOf(".") != -1)
                {
                    money = money.Remove(money.IndexOf("."), 1);
                    isPoint = true;
                }
                for (int i = money.Length; i > 0; i--)
                {
                    int MyData = Convert.ToInt16(money[money.Length - i].ToString());
                    M += MyBase[MyData];
                    if (isPoint == true)
                    {
                        M += MyScale[i - 1];
                    }
                    else
                    {
                        M += MyScale[i + 1];
                    }
                }
                return M;
            }

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  • 原文地址:https://www.cnblogs.com/axinno1/p/2580981.html
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