一、数组 - Array
var types = ["none","warning","error"]//省略类型的数组声明 var menbers = [String]()//声明一个空数组 menbers.append("six") //添加元素 menbers += ["seven"] //添加元素 menbers.insert("one", at: 0)//指定位置添加元素 menbers[0] = "message" //通过下标修改数组中的数据 menbers[0...2] = ["message","hangge","com"] //通过小标区间替换数据(前3个数据) menbers.count // 获取数组元素个数 menbers.isEmpty //判断数组是否为空 //交换元素位置(第2个和第3个元素位置进行交换) menbers.swapAt(1, 2) menbers.remove(at: 2)//删除下标为2的数组 menbers.removeLast()//删除最后一个元素 menbers.removeAll(keepingCapacity: true)//删除数组中所有元素 let addStringArr = types + menbers//数组组合 //使用for in 实现数组遍历 for value in menbers{ print("(value)") } //通过enumerate函数同时遍历数组的所有索引与数据 for(index,value) in menbers.enumerated(){ print("索引:(index) 数据:(value)"); } //过滤数组元素 let newTypes = types.filter { $0.count < 6 } //["none", "error"]
二、字典 - Dictionary(即键值对)
var empty = [String:Int]() //建立个空字典 var myDic = ["name":"hangge","url":"hangge.com"]//声明一个字典 myDic["address"] = "china"//添加或修改key值 myDic.removeValue(forKey: "name")//删除“name”这个key值 myDic["name"] = nil //同样可以删除“name”这个key值 myDic.keys //访问字典的key集合 // print(myDic.values) //访问字典的values集合 //遍历字典 for(key,value) in myDic{ print("(key):(value)"); } //只遍历字典的键(key) for key in myDic.keys{ print("(key)"); } //只遍历字典的值(value) for value in myDic.values{ print("(value)"); }
2,其它几种创建字典的方法
(1)通过元组创建字典
let tupleArray = [("Monday",30),("Tuesday",25),("Wednesday",27)] let dictionary = Dictionary(uniqueKeysWithValues: tupleArray) print(dictionary)
(2)通过键值序列创建字典
let names = ["Apple", "Pear"] let prices = [7, 6] let dict = Dictionary(uniqueKeysWithValues: zip(names, prices)) print(dict);
(3)只有键序列、或者值序列创建字典
let array = ["Monday","Tuesday","Wednesday"] let dict1 = Dictionary(uniqueKeysWithValues:zip(1..., array)) let dict2 = Dictionary(uniqueKeysWithValues:zip(array, 1...)) print("dict1:(dict1)") print("dict2:(dict2)")
(4)字典分组(比如下面生成一个以首字母分组的字典)
let names = ["Apple","Pear","Grape","Peach"] let dict = Dictionary(grouping:names){ $0.first!} print(dict)
3,重复键的处理
(1)zip配合速记+可以用来解决重复键的问题(相同的键值相加)
let array = ["Apple","Pear","Pear","Orange"] let dic = Dictionary(zip(array, repeatElement(1, count: array.count)),uniquingKeysWith: +) print(dic)
(2)下面使用元组创建字典时,遇到相同的键则取较小的那个值
let duplicatesArray = [("Monday",30),("Tuesday",25),("Wednesday",27),("Monday",28)] let dic = Dictionary(duplicatesArray, uniquingKeysWith:min) print(dic) // ["Monday": 28, "Tuesday": 25, "Wednesday": 27]
4,字典合并
想要将一些序列、或者字典合并到现有的字典中,可以借助如下两个合并方法:
- merge(_: uniquingKeysWith:):这种方法会修改原始Dictionary
- merging(_: uniquingKeysWith:):这种方法会创建并返回一个全新的Dictionary
var dic = ["one":10,"two":20] //merge方法合并 let tuples = [("one",5), ("three",30)] dic.merge(tuples, uniquingKeysWith: min) print(dic);//["one": 5, "three": 30, "two": 20] //merging 方法合并 let dic2 = ["one":0,"four":40] let dic3 = dic.merging(dic2, uniquingKeysWith: min) print(dic3)//["three": 30, "four": 40, "one": 0, "two": 20]
5,默认值
(1)过去我们如果希望当某个字典值不否存在时,使用一个指定的默认值,这个通常会使用if let来判断实现。
let dic = ["apple":1,"banana":2] var orange:Int if let value = dic["orange"]{ orange = value }else{ orange = 0 } print(orange)//打印0
(2)到了 Swift4,我们可以直接指定一个默认值,如果不存在该键值时名,会直接返回这个值。下面代码的效果同上面是一样的。
let dic = ["aaple":1,"banana":2] let orange = dic["orange", default:0] print(orange)//打印0
(3)下面是统计一个字符串中所有单词出现的次数。可以看到了有了默认值,实现起来会简单许多。
let str = "apple banana orange apple banana" var wordsCount: [String: Int] = [:] for word in str.split(separator:" "){ wordsCount["(word)", default:0] += 1 } print(wordsCount)//["apple": 2, "orange": 1, "banana": 2]
三、结构体 - struct
struct BookInfo { var ID:Int = 0 var Name:String = "Defaut" var Author:String = "Defaut" } var book1:BookInfo//默认构造器创建结构体实现 var book2 = BookInfo(ID: 0021, Name: "白白", Author: "baibai")//调用逐一构造器创建实列 book2.ID = 1234 //修改内部值
四、枚举 - enum
enum CompassPoint{ case north case south case east case west } enum Planet:Int{ case mercury = 1 case venus = 2 case earth = 3 } enum Direction{ case up case down func description() -> String { switch self { case .up: return "向上" case .down: return "向下" } } } var dirctionToHead = CompassPoint.west let earthsOrder = Planet.earth.rawValue //rawValue来获取他的原始值:3 let possiblePlanet = Planet(rawValue: 2) //通过原始值来寻找所对应的枚举成员:Venus print(dirctionToHead) print(earthsOrder) print(possiblePlanet) print(Direction.up.description())