怎样判断用户输入的是否为数字 续

判断输入是否为数字 续

这里用到了检测与处理异常的try-except语句。
下面是一个例子，在Python交互环境执行的：
>>> a = int(raw_input('Please input an integer ... '))
Please input an int number ... t
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 't'

那么，如果使用了try-except语句，结果就是这样的。
>>> try:
...     a = int(raw_input('Please input an integer ... '))
... except ValueError, error_info:
...     print error_info
...
Please input an int number ... t
invalid literal for int() with base 10: 't'

我们可以把这段代码更加完善成，如果用户没有输入数字，就一直叫用户重新尝试。

>>> trigger = True
>>> while trigger:
...     try:
...             trigger = False
...             a = int(raw_input('Please input an integer ... '))
...     except ValueError:
...             trigger = True
...             print 'You did not input an integer, try again ... '
...
Please input an integer ... a
You did not input an integer, try again ...
Please input an integer ... 1.1
You did not input an integer, try again ...
Please input an integer ... *
You did not input an integer, try again ...
Please input an integer ... @
You did not input an integer, try again ...
Please input an integer ... 0.
You did not input an integer, try again ...
Please input an integer ... 0
>>>

这里有个新问题，程序会把数字0.也认为不是一个整数。会有更好的处理办法吗？

下面是检测与处理异常的try-except语句的一个典型例子。能帮助你理解try-except语句。

>>> 1/0
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ZeroDivisionError: integer division or modulo by zero

>>> try:
...     1/0
... except ZeroDivisionError, e:
...     print e
...
integer division or modulo by zero
>>>