《c程序设计语言》读书笔记-第二个字符串任意一个在第一个字符串出现的位置，未出先返回-1

#include <stdio.h>
#include <string.h>

#define Num 1000


int main()
{
    int  c,i,j = 0,m = 0,n = 0,k,count1 = 0,count2 = 0,w,h = 0,l = 0,flag2 = 0;
    char s[Num],t[Num],str[Num] = {''};
    int  number[Num],number2[Num],flag = 0;

    printf("Please input a string:
");

    while((c = getchar()) != EOF && c != '
' && count1 < Num)
    {
        s[count1] = c;
        count1++;
    }

    printf("Please input another string:
");

     while((c = getchar()) != EOF && c != '
' && count2 < Num)
    {
        t[count2] = c;
        count2++;
    }


    for(i = 0;i < count1;i++)
    {
        flag = 0;

        for(k = 0;k < m;k++)
        {
            if(s[i] == str[k])
                {
                    flag = 1;
                    break;
                }
        }

        if(flag == 0)
        {
            for(j = 0;j < count2;j++)
            {
                if(s[i] == t[j])
                {
                    str[m++] = s[i];
                    number[n++] = i;
                    number2[h++] = j;
                    break;
                }
            }
        }
    }
    printf("The first location in str1 where any character from str2 occurs
");

    for(w = 0;w < count2;w++)
        {
            flag2 = 0;

            for(l = 0;l < m;l++)
                {
                    if(w == number2[l])
                    {
                        printf("%c",str[l]);
                        printf(",%d
",number[l]);
                        flag2 = 1;
                        break;
                    }
                }
            if(flag2 == 0)
                 printf("%c,-1
",t[w]);

        }

    return 0;
}

费了好大劲，完成期间错误百出！要仔细点啊。