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  • 力扣 54 螺旋矩阵 方向键 || 剑指 Offer 29. 顺时针打印矩阵

    题目链接

    **思路 : **使用方向键,或者模拟(模拟太容易出问题,建议使用方向键)。
    代码

        public List<Integer> spiralOrder(int[][] matrix) {
            List<Integer> list = new ArrayList<>();
            if(matrix == null || matrix.length == 0 || matrix[0].length == 0) {
                return list;
            }
            
            int m = matrix.length;
            int n = matrix[0].length;
    
            int [][]vis = new int[m][n];
    
            int index = 1;
            // 右下左上
            int [][]dir = {
                    {0, 1}, {1, 0}, {0, -1}, {-1, 0}
            };
    
            int si = 0, sj = 0;
            // 临时判断使用
            int fi = 0, fj = 0;
            list.add(matrix[0][0]);
            vis[0][0] = 1;
            int direction = 0;
            for (int i = 1; i < m * n; i++) {
                fi = si + dir[direction][0];
                fj = sj + dir[direction][1];
    
                // 不能一直往一个方向,就转向
                if (!(fi >= 0 && fi < m && fj >= 0 && fj < n && vis[fi][fj] == 0)) {
                    direction = (direction + 1) % 4;
                }
    
                si += dir[direction][0];
                sj += dir[direction][1];
                list.add(matrix[si][sj]);
                vis[si][sj] = 1;
            }
            return list;
        }
    

    代码

        public int[] spiralOrder(int[][] matrix) {
            if (matrix == null || matrix.length < 1 || matrix[0].length < 1) return new int[0];
    
            int sum = matrix[0].length * matrix.length;
    
            int [][]vis = new int[matrix.length][matrix[0].length];
    
            int column = matrix[0].length, row = matrix.length;
            int []ans = new int[sum];
    
            int count = 1;
    
            // 表示右下左上方向
            int [][]dir = {
                    {0, 1}, {1, 0}, {0, -1}, {-1, 0}
            };
    
            int si = 0, sj = 0;
            ans[0] = matrix[0][0];
            vis[0][0] = 1;
            while (count < sum) {
                for (int i = 0; i < 4; i++) {
                    si += dir[i][0];
                    sj += dir[i][1];
    
                    //System.out.println("si: " + si + " sj : " + sj);
                    // 表单方向一致前进
                    while (si >= 0 && si < row && sj >= 0 && sj < column && vis[si][sj] == 0) {
                        vis[si][sj] = 1;
    
                        //System.out.print(matrix[si][sj] + " ");
                        ans[count++] = matrix[si][sj];
    
                        si += dir[i][0];
                        sj += dir[i][1];
                    }
    
                    //System.out.println();
    
                    // 此时需要回退
                    si -= dir[i][0];
                    sj -= dir[i][1];
                }
            }
    
            return ans;
        }
    
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  • 原文地址:https://www.cnblogs.com/bears9/p/13544334.html
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