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![]() We know that the moment of inertia for hoop with radius R is mR2. We can divide cylinder into thin concentric hoops of thickness dR. Density = Mass per unit volume Density = dm / dV ![]() where:Lets assume height of the cylinder is h. ![]() we have ![]() ![]() We can obtain moment of inertia by integrating over all these hoops ![]() ![]() Cylinder has uniform density, where þ = constant ![]() ![]() ![]() Volume of this cylinder is ![]() ![]() Mass M is ![]() ![]() since ![]() ![]() Moment of inertia for hollow cylinder is ![]() |