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  • 860. Lemonade Change

    At a lemonade stand, each lemonade costs $5.

    Customers are standing in a queue to buy from you, and order one at a time (in the order specified by bills).

    Each customer will only buy one lemonade and pay with either a $5, $10, or $20 bill. You must provide the correct change to each customer, so that the net transaction is that the customer pays $5.

    Note that you don't have any change in hand at first.

    Return true if and only if you can provide every customer with correct change.

    Example 1:

    Input: [5,5,5,10,20]
    Output: true
    Explanation:
    From the first 3 customers, we collect three $5 bills in order.
    From the fourth customer, we collect a $10 bill and give back a $5.
    From the fifth customer, we give a $10 bill and a $5 bill.
    Since all customers got correct change, we output true.

    Example 2:

    Input: [5,5,10]
    Output: true

    Example 3:

    Input: [10,10]
    Output: false

    Example 4:

    Input: [5,5,10,10,20]
    Output: false
    Explanation:
    From the first two customers in order, we collect two $5 bills.
    For the next two customers in order, we collect a $10 bill and give back a $5 bill.
    For the last customer, we can't give change of $15 back because we only have two $10 bills.
    Since not every customer received correct change, the answer is false.

    Note:

    0 <= bills.length <= 10000
    bills[i] will be either 5, 10, or 20.
    
    class Solution:
        def lemonadeChange(self, bills):
            """
            :type bills: List[int]
            :rtype: bool
            """
            a,b = 0,0
            for i in bills:
                if i == 5:
                    a += 1
                    continue
                if i ==10:
                    a -= 1
                    if a<0:
                        return False
                    b += 1
                if i == 20:
                    if b>0:
                        b -= 1
                        a -= 1
                        if a<0 or b<0:
                            return False
                    else:
                        a -= 3
                        if a<0:
                            return False
            return True
    
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  • 原文地址:https://www.cnblogs.com/bernieloveslife/p/9717838.html
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