We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).
Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example 1:
Input:
bits = [1, 0, 0]
Output: True
Explanation:
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.
Example 2:
Input:
bits = [1, 1, 1, 0]
Output: False
Explanation:
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.
Note:
1 <= len(bits) <= 1000.
bits[i] is always 0 or 1.
class Solution:
def isOneBitCharacter(self, bits):
"""
:type bits: List[int]
:rtype: bool
"""
i = 0
while i <len(bits)-1:
if bits[i]==0:
i += 1
continue
if bits[i]==1:
i += 2
continue
if i==len(bits)-1:
return True
else:
return False