Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
Example 1:
Input: s = "egg", t = "add"
Output: true
Example 2:
Input: s = "foo", t = "bar"
Output: false
Example 3:
Input: s = "paper", t = "title"
Output: true
Note:
You may assume both s and t have the same length.
class Solution:
def isIsomorphic(self, s, t):
"""
:type s: str
:type t: str
:rtype: bool
"""
dict = {}
for i in range(len(s)):
if not dict.__contains__(s[i]):
dict[s[i]] = t[i]
else:
if dict.get(s[i]) != t[i]:
return False
dict.clear()
for i in range(len(t)):
if not dict.__contains__(t[i]):
dict[t[i]] = s[i]
else:
if dict.get(t[i]) != s[i]:
return False
return True