HDU-1002.大数相加(字符串模拟)

　　本题大意：给出两个1000位以内的大数a 和b，让你计算a + b的值。

　　本题思路：字符串模拟就能过，会Java的大佬应该不会点进来......

　　参考代码：

#include <cstdio>
#include <cstring>
using namespace std;

const int maxn = 1000 + 5;
int  t, Case = 0, now;
int ans[maxn];
char s1[maxn], s2[maxn];

int main () {
    scanf("%d", &t);
    while(t --) {
        if(Case > 0) printf("
");
        now = 0;
        memset(ans, 0, sizeof(ans));
        scanf("%s %s", s1, s2);
        int len1 = strlen(s1), len2 = strlen(s2), i = len1 - 1, j = len2 - 1;
        while(i >= 0 && j >= 0) {
            ans[now + 1] =  (ans[now] + s1[i] + s2[j] - 2 * '0') / 10;
            ans[now] = (ans[now ++] + s1[i --] + s2[j --] - 2 * '0') % 10;
        }
        while(i >= 0) {
            ans[now + 1] = (ans[now] + s1[i] - '0') / 10;
            ans[now] = (ans[now ++] + s1[i --] - '0') % 10;
        }
        while(j >= 0) {
            ans[now + 1] = (ans[now] + s2[j] - '0') / 10;
            ans[now] = (ans[now ++] + s2[j --] - '0') % 10;
        }
        printf("Case %d:
%s + %s = ", ++ Case, s1, s2);
        if(ans[now] > 0)    now ++;
        for(i = now - 1; i >= 0; i --)
            printf("%d", ans[i]);
        printf("
");
    }
    return 0;
}