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  • 求出在某个经纬度方圆多少公里返回的最大最小经纬度

    java代码,计算在地图上某个点,以这个点为中心,覆盖若干公里范围的最大和最小经纬度

    package test;
    
    public class MainClass {
    
        public final static class GpsUtil {
            double pi;
            double distance;
    
            //地球平均半径6371km
            public static final double EARTH_RADIUS = 6371000;
    
            public GpsUtil() {
                this.pi = Math.PI;//3.141592654;
                //测试好久,发现3535出来的是附近五公里- -!
                distance = 3535;
            }
    
            /**
             * 
             * @param lat 维度
             * @param lon 经度
             * @param distance 多少米范围
             * @return
             */
            public double[] compute(double lat, double lon, double distance) {
                
                lat = lat * pi / 180;
                lon = lon * pi / 180;  //先换算成弧度
                double rad_dist = distance / EARTH_RADIUS;  //计算X公里在地球圆周上的弧度
                double lat_min = lat - rad_dist;
                double lat_max = lat + rad_dist;   //计算纬度范围
                double lon_min;
                double lon_max;
                //因为纬度在-90度到90度之间,如果超过这个范围,按情况进行赋值
                if (lat_min > -pi / 2 && lat_max < pi / 2) {
                    //开始计算经度范围
                    double lon_t = Math.asin(Math.sin(rad_dist) / Math.cos(lat));
                    lon_min = lon - lon_t;
                    //同理,经度的范围在-180度到180度之间
                    if (lon_min < -pi)
                        lon_min += 2 * pi;
                    lon_max = lon + lon_t;
                    if (lon_max > pi)
                        lon_max -= 2 * pi;
                } else {
                    lat_min = Math.max(lat_min, -pi / 2);
                    lat_max = Math.min(lat_max, pi / 2);
                    lon_min = -pi;
                    lon_max = pi;
                }
                //最后置换成角度进行输出
                lat_min = lat_min * 180 / pi;
                lat_max = lat_max * 180 / pi;
                lon_min = lon_min * 180 / pi;
                lon_max = lon_max * 180 / pi;
                double result[] = { lat_min, lat_max, lon_min, lon_max };
                return result;
            }
    
            /**
             * 转化为弧度(rad)
             */
            private double rad(double d) {
                return d * Math.PI / 180.0;
    //            return d;
            }
    
            /**
             * 基于余弦定理求两经纬度距离
             * 
             * @param lon1
             *            第一点的精度
             * @param lat1
             *            第一点的纬度
             * @param lon2
             *            第二点的精度
             * @param lat2
             *            第二点的纬度
             * @return 返回的距离,单位m
             */
    
            public double LantitudeLongitudeDist(double lat1, double lat2, double lon1, double lon2) {
                double radLat1 = rad(lat1);
                double radLat2 = rad(lat2);
    
                double radLon1 = rad(lon1);
                double radLon2 = rad(lon2);
    
                if (radLat1 < 0)
                    radLat1 = Math.PI / 2 + Math.abs(radLat1);// south  
                if (radLat1 > 0)
                    radLat1 = Math.PI / 2 - Math.abs(radLat1);// north  
                if (radLon1 < 0)
                    radLon1 = Math.PI * 2 - Math.abs(radLon1);// west  
                if (radLat2 < 0)
                    radLat2 = Math.PI / 2 + Math.abs(radLat2);// south  
                if (radLat2 > 0)
                    radLat2 = Math.PI / 2 - Math.abs(radLat2);// north  
                if (radLon2 < 0)
                    radLon2 = Math.PI * 2 - Math.abs(radLon2);// west  
                double x1 = EARTH_RADIUS * Math.cos(radLon1) * Math.sin(radLat1);
                double y1 = EARTH_RADIUS * Math.sin(radLon1) * Math.sin(radLat1);
                double z1 = EARTH_RADIUS * Math.cos(radLat1);
    
                double x2 = EARTH_RADIUS * Math.cos(radLon2) * Math.sin(radLat2);
                double y2 = EARTH_RADIUS * Math.sin(radLon2) * Math.sin(radLat2);
                double z2 = EARTH_RADIUS * Math.cos(radLat2);
    
                double d = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2) + (z1 - z2) * (z1 - z2));
                //余弦定理求夹角  
                double theta = Math.acos((EARTH_RADIUS * EARTH_RADIUS + EARTH_RADIUS * EARTH_RADIUS - d * d)
                        / (2 * EARTH_RADIUS * EARTH_RADIUS));
                double dist = theta * EARTH_RADIUS;
                return dist;
            }
    
        }
    
        public static void main(String[] args) {
            GpsUtil gps = new GpsUtil();
            double[] a = gps.compute(30.01254012452224, 121.01244544525456456478797, 3535);
            for (double d : a) {
                System.out.println(d);
            }
    
            double dis = gps.LantitudeLongitudeDist(a[0], a[1], a[2], a[3]);
            System.out.println("两点之间距离:" + dis + "米");
    
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/bigben0123/p/9663384.html
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