将泛型列表List<T>转换为指定属性的XML

一般的　对象序列化成对象都是这样的

<?xml version="1.0" encoding="utf-8" ?>
<BaseInfo>
  <Person>
    <Name>小明</Name>
    <Age>16</Age>
    <Books>
      <Book>
        <ISBN>123</ISBN>
        <Title>借的书1</Title>
      </Book>
    </Books>
  </Person>
  <Person>
    <Name>小红</Name>
    <Age>18</Age>
    <Books>
      <Book>
        <ISBN>456</ISBN>
        <Title>借的书2</Title>
      </Book>
      <Book>
        <ISBN>789</ISBN>
        <Title>借的书3</Title>
      </Book>
    </Books>
  </Person>
</BaseInfo>

这样的代码要求层次比较清晰，没办法序列化成这样

<?xml version="1.0" encoding="utf-8"?>
<datapacket wsid="EDIS_SORESULT_ERP" errcode="" errmsg="">
  <rowsdata a="" b="" c="" />
</datapacket>

解决方案一：

通过反射和xml.linq来组装指定的对象：

 public static XDocument BuildXML<T>(List<T> data, string functionName = "")
        {
            XDocument xDocument = new XDocument();
            Type type = typeof(T);
            var properties = type.GetProperties();//获取属性
            XElement xElements = new XElement("datapacket",
                new XAttribute("wsid", functionName),
                new XAttribute("errcode", ""),
                new XAttribute("errmsg", ""),
                new XElement("rowsdata",
                data.Select(i => new XElement("row", properties.Select(p => new XAttribute(p.Name, p.GetValue(i)))
                ))));
            xDocument.Add(xElements);
            return xDocument;
        }

待反射对象：

public class EDIS_SORESULT_CFM_DTO
    {
        public string EDIS_SORESULT_SEQID { get; set; }
        public string EDIS_CONSIGNOR { get; set; }
        public string IMP_PROCESS_FLAG { get; set; }
    }
//初始化
 public List<EDIS_SORESULT_CFM_DTO> InitDemoList()
        {
            return new List<EDIS_SORESULT_CFM_DTO> {
                new EDIS_SORESULT_CFM_DTO {EDIS_CONSIGNOR="a1",EDIS_SORESULT_SEQID="a2",IMP_PROCESS_FLAG="a3" },
                new EDIS_SORESULT_CFM_DTO {EDIS_CONSIGNOR="b1",EDIS_SORESULT_SEQID="b2",IMP_PROCESS_FLAG="b3"  },
                new EDIS_SORESULT_CFM_DTO {EDIS_CONSIGNOR="c1",EDIS_SORESULT_SEQID="c2",IMP_PROCESS_FLAG="c3"  }
            };
        }

调用：

BuildXML(data, "EDIS_SORESULT_ERP")

预计返回结果：

<?xml version="1.0" encoding="utf-8"?>
<datapacket wsid="EDIS_SORESULT_ERP" errcode="" errmsg="">
  <rowsdata>
    <row EDIS_SORESULT_SEQID="a2" EDIS_CONSIGNOR="a1" IMP_PROCESS_FLAG="a3" />
    <row EDIS_SORESULT_SEQID="b2" EDIS_CONSIGNOR="b1" IMP_PROCESS_FLAG="b3" />
    <row EDIS_SORESULT_SEQID="c2" EDIS_CONSIGNOR="c1" IMP_PROCESS_FLAG="c3" />
  </rowsdata>
</datapacket>

解决方案二：

直接在对象上加属性，但是这种方法只适合单个对象，如果是对象列表就不适合了

对象修改如下：

public class EDIS_SORESULT_CFM_DTO
    {
        [System.Xml.Serialization.XmlAttributeAttribute()]
        public string EDIS_SORESULT_SEQID { get; set; }
        [System.Xml.Serialization.XmlAttributeAttribute()]
        public string EDIS_CONSIGNOR { get; set; }
        public string IMP_PROCESS_FLAG { get; set; }
    }

具体代码如下：

 EDIS_SORESULT_CFM_DTO myObject = new EDIS_SORESULT_CFM_DTO { EDIS_CONSIGNOR = "a1", EDIS_SORESULT_SEQID = "a2", IMP_PROCESS_FLAG = "a3" };
            // Insert code to set properties and fields of the object.  
            XmlSerializer mySerializer = new
            XmlSerializer(typeof(EDIS_SORESULT_CFM_DTO));
            // To write to a file, create a StreamWriter object.  
            StreamWriter myWriter = new StreamWriter(@"d:/myFileName.xml");
            mySerializer.Serialize(myWriter, myObject);
            myWriter.Close();

返回结果：

<?xml version="1.0" encoding="utf-8"?>
<EDIS_SORESULT_CFM_DTO xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" EDIS_SORESULT_SEQID="a2" EDIS_CONSIGNOR="a1">
  <IMP_PROCESS_FLAG>a3</IMP_PROCESS_FLAG>
</EDIS_SORESULT_CFM_DTO>

参考：

c# - How to serialize a List<T> into XML? - Stack Overflow

XDocument简单入门 - hello*boy - 博客园 (cnblogs.com)

如何：序列化对象 | Microsoft Docs