struct LeftTree{
int l,r,val,dis;
}t[N];
int fa[N];
inline int Find(int x){
return x == fa[x] ? x : fa[x] = Find(fa[x]);
}
inline int Merge(int x, int y){
if(!x) return y;
if(!y) return x;
if(t[x].val < t[y].val || (t[x].val == t[y].val && x > y)) Swap(x, y);
t[x].r = Merge(t[x].r, y);
fa[t[x].r] = fa[t[x].l] = x;
if(t[t[x].r].dis > t[t[x].l].dis) Swap(t[x].r, t[x].l);
t[x].dis = t[t[x].r].dis + 1;
return x;
}
int main(){
int n,m;
while(~scanf("%d", &n)){
R(i,1,n){
t[i].l = t[i].r = t[i].dis = 0;
io >> t[i].val;
fa[i] = i;
}
io >> m;
while(m--){
int x,y;
io >> x >> y;
x = Find(x), y = Find(y);
if(x == y){
printf("-1
"); continue;
}
t[x].val >>= 1;
int rt = Merge(t[x].l, t[x].r); // the left and right united and elected the new king
t[x].l = t[x].r = 0; // the old king lost everything
x = Merge(x, rt); // the fight between the old and the new, only the winner was deserved to be king
t[y].val >>= 1;
rt = Merge(t[y].l, t[y].r);
t[y].l = t[y].r = 0;
y = Merge(y, rt);
rt = Merge(x, y); // the winner of the two groups
fa[x] = fa[y] = rt; // ought to rule the union
printf("%d
", t[rt].val);
}
}
return 0;
}