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  • POJ2201 Cartesian Tree (cartesian tree)

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define	D_e(x)	cout << #x << " = " << x << endl
    
    #else
    
    #define D_e_Line ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std; 
    
    const int N = 50007;
    
    struct node{
    	int l,r,fa,id;
    	int val,pri;
    	bool operator < (const node &com)const{
    		return val < com.val;
    	}
    }t[N],ans[N];
    
    inline void Insert(int rt){
    	int tmp;
    	for(tmp = rt - 1; t[tmp].pri > t[rt].pri; tmp = t[tmp].fa);
    	t[rt].l = t[tmp].r;
    	t[t[tmp].r].fa = rt;
    	t[rt].fa = tmp;
    	t[tmp].r = rt;
    }
    
    int vis[30007];
    int main(){
        int n;
        while(scanf("%d", &n) != EOF){
            Fill(vis, false);
            int flag = true;
    	    R(i,0,n){
    	        t[i].l = t[i].r = t[i].fa = 0;
    	        t[i].w = -0x7fffffff;
    	    }
     
            R(i,1,n){
                scanf("%d%d", &t[i].val, &t[i].w);
                t[i].id = i;
                if(vis[t[i].val])
                    flag = false;
                else
                    vis[t[i].val] = true;
            }
            if(!flag){
            	printf("NO
    ");
            	continue;
            }
            printf("YES
    ");
            
    		sort(t + 1, t + n + 1);
    		
            R(i,1,n) Insert(i);
    
            R(i,1,n){
                if(!t[i].l)
                    ans[t[i].id].l = 0;
                else
                    ans[t[i].id].l = t[t[i].l].id;
                if(!t[i].r)
                    ans[t[i].id].r = 0;
                else
                    ans[t[i].id].r = t[t[i].r].id;
                if(!t[i].fa)
                    ans[t[i].id].fa = 0;
                else
                    ans[t[i].id].fa = t[t[i].fa].id;
            }
            
            R(i,1,n)
                printf("%d %d %d
    ", ans[i].fa, ans[i].l, ans[i].r);
        }
        
        return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11194779.html
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