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  • Luogu3379 【模板】最近公共祖先(LCA) (倍增LCA)

    蒟蒻又来复习模板了。还WA了两次

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    
    #else
    
    #define D_e_Line ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    const int N  = 500007;
    
    struct Edge{
        int nxt, pre;
    }e[N << 1];
    int head[N], cntEdge;
    inline void add(int u, int v){
        e[++cntEdge] = (Edge){head[u], v}, head[u] = cntEdge;
    }
    
    int f[N][22], lg[N], dep[N];
    
    inline void DFS(int u, int fa){
        dep[u] = dep[fa] + 1, f[u][0] = fa;
        for(register int i = 1; (1 << i) <= dep[u]; ++ i){
            f[u][i] = f[f[u][i - 1]][i - 1];
        }
        for(register int i = head[u]; i; i = e[i].nxt){
            int v = e[i].pre;
            if(v == fa) continue;
            DFS(v, u);
        }
    }
    
    
    inline int LCA(int x, int y){
        if(dep[x] < dep[y]) Swap(x, y);
        while(dep[x] > dep[y]){
            x = f[x][lg[dep[x] - dep[y]] - 1];
        }
        if(x == y) return x;
        nR(k,lg[dep[x]] - 1,0){
            if(f[x][k] != f[y][k]){
                x = f[x][k];
                y = f[y][k];
            }
        }
        return f[x][0];
    }
    
    int main(){
    
        int n, Ques, root;
        io >> n >> Ques >> root;
        R(i,1,n-1){
        	int u, v;
        	io >> u >> v;
        	add(u, v);
        	add(v, u);
        }
        
        //log(n) + 1
        R(i,1,n)
            lg[i] = lg[i-1] + ((1 << lg[i - 1]) == i);
        
        DFS(root,0);
        
        while(Ques--){
        	int x, y;
        	io >> x >> y;
        	printf("%d
    ", LCA(x, y));
        }
    
        return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11217479.html
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