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  • Luogu3402【模板】可持久化并查集 (主席树)

    (depth)按秩合并,不能直接启发,数组开40倍左右

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    //#define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int N = 200005;
    
    int n;
    
    int T[N], L[N * 40], R[N * 40];
    int fa[N * 40], dep[N * 40];
    int treeIndex; 
    
    #define lson L[rt], l, mid
    #define rson R[rt], mid + 1, r
    inline void Build(int &rt, int l, int r){
    	rt = ++treeIndex;
    	if(l == r){
    		fa[rt] = l;
    		return;
    	}
    	int mid = (l + r) >> 1;
    	Build(lson), Build(rson);
    }
    inline void Merge(int &rt, int pre, int l, int r, int x, int father){
    	rt = ++treeIndex;
    	if(l == r){
    		fa[rt] = father;
    		dep[rt] = dep[pre]; // inherit the last depth to union by rank
    		return;
    	}
    	L[rt] = L[pre], R[rt] = R[pre]; // don't forget initial this
    	int mid = (l + r) >> 1;
    	if(x <= mid)
    		Merge(L[rt], L[pre], l, mid, x, father);
    	else
    		Merge(R[rt], R[pre], mid + 1, r, x, father);
    }
    inline int Query(int rt, int l, int r, int x){
    	if(l == r) return rt;
    	int mid = (l + r) >> 1;
    	if(x <= mid)
    		return Query(lson, x);
    	else
    		return Query(rson, x);
    }
    inline void AddDepth(int rt, int l, int r, int x){
    	if(l == r){
    		++dep[rt]; return;
    	}
    	int mid = (l + r) >> 1;
    	if(x <= mid)
    		AddDepth(lson, x);
    	else
    		AddDepth(rson, x);
    }
    inline int Find(int rt, int x){
    	int fx = Query(rt, 1, n, x);
    	return x == fa[fx] ? fx : Find(rt, fa[fx]);
    }
    
    int main()
    {
    	FileOpen();
    	int m;
        io >> n >> m;
        
    	Build(T[0],1,n);
        
        R(i,1,m){
        	int opt;
        	io >> opt;
        	switch(opt){
        		case 1:{
        			T[i] = T[i - 1]; // inherit the last edition
        			
        			int x, y;
        			io >> x >> y;
        			int fx = Find(T[i], x), fy = Find(T[i], y);
        			if(fa[fx] == fa[fy]) continue; 
        			if(dep[fx] > dep[fy]) Swap(fx, fy); // lighter lord heavier
        			Merge(T[i], T[i - 1], 1, n, fa[fx], fa[fy]);
        			if(dep[fx] == dep[fy]) AddDepth(T[i], 1, n, fa[fy]);
        			break;
        		}
        		case 2:{
        			int x;
        			io >> x;
        			T[i] = T[x];
        			break;
        		}
        		case 3:{
        			T[i] = T[i - 1]; // inherit the last edition
        			
        			int x, y;
        			io >> x >> y;
        			int fx = Find(T[i], x), fy = Find(T[i], y);
    
        			if(fa[fx] == fa[fy])
        				printf("1
    ");
        			else
        				printf("0
    ");
        			break;
        		}
        	}
        }
        
      	return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11223886.html
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