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  • Luogu5367 【模板】康托展开 (康拓展开)

    (n^2)暴力

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int mod = 998244353;
    
    int fac[1000007];
    
    int n;
    inline int Cantor(int *a, int n){
    	int ans = 1, sum = 0;
    	R(i,1,n){
    		R(j,i+1,n){
    			sum += (a[i] > a[j]);
    			if(sum > mod) sum -= mod;
    		}
    		ans = (ans + 1ll * sum * fac[n - i] % mod) % mod;
    		sum = 0;
    	}
    	return ans;
    }
    
    int a[1000007];
    int main(){
        int n;
        io >> n;
        fac[0] = 1;
        R(i,1,n){
    		io >> a[i];
    		fac[i] = 1ll * fac[i - 1] * i % mod;
    	}
    	
    	printf("%d", Cantor(a, n));
    
        return 0;
    }
    

    BIT优化

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Abs(a) ((a) < 0 ? -(a) : (a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt","r",stdin);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x)  ;
    #define Pause() ;
    #define FileOpen() ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int N = 1000007;
    const int mod = 998244353;
    
    int n;
    
    int t[N];
    inline void Updata(int x, int w){
    	for(; x <= n; x += x&-x) t[x] += w;
    }
    inline int Query(int x){
    	int sum = 0;
    	for(; x; x -= x&-x) sum += t[x];
    	return sum;
    }
    
    int a[N];
    int main(){
    	//FileOpen();
    	
        io >> n;
    	int fac = 1;
        nR(i,n,1){
        	io >> a[i];
        }
        
        int ans = 0;
        R(i,1,n){
        	int sum = Query(a[i]);
            ans = (ans + 1ll * fac * sum % mod) % mod;
    		fac = 1ll * fac * i % mod;
            Updata(a[i], 1);
        }
        
    	printf("%d
    ", ans + 1);
    	
        return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11231013.html
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