Luogu4084 [USACO17DEC]Barn Painting （树形DP）

数组越界那个RE+WA的姹紫嫣红的。。。
乘法原理求种类数，类似于没有上司的舞会。

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
#define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
#define Max(a,b) ((a) > (b) ? (a) : (b))
#define Min(a,b) ((a) < (b) ? (a) : (b))
#define Fill(a,b) memset(a, b, sizeof(a))
#define Abs(a) ((a) < 0 ? -(a) : (a))
#define Swap(a,b) a^=b^=a^=b
#define ll long long

#define ON_DEBUG

#ifdef ON_DEBUG

#define D_e_Line printf("

----------

")
#define D_e(x)  cout << #x << " = " << x << endl
#define Pause() system("pause")
#define FileOpen() freopen("in.txt","r",stdin);

#else

#define D_e_Line ;
#define D_e(x)  ;
#define Pause() ;
#define FileOpen() ;

#endif

struct ios{
    template<typename ATP>ios& operator >> (ATP &x){
        x = 0; int f = 1; char c;
        for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
        while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
        x*= f;
        return *this;
    }
}io;
using namespace std;

const int N = 100007;
const int mod = 1000000007;

struct Edge{
	int nxt, pre;
}e[N << 1];
int head[N], cntEdge;
inline void add(int u, int v){
	e[++cntEdge] = (Edge){head[u], v}, head[u] = cntEdge;
}

int col[N];
long long f[N][3];
inline void DFS(int u, int fa){
	if(col[u])
		f[u][col[u] - 1] = 1;
	else{
		R(i,0,2)
			f[u][i] = 1;
	}
	for(register int i = head[u]; i; i = e[i].nxt){
		int v = e[i].pre;
		if(v == fa) continue;
		DFS(v, u);
		f[u][0] = f[u][0] * (f[v][1] + f[v][2]) % mod;
		f[u][1] = f[u][1] * (f[v][0] + f[v][2]) % mod;
		f[u][2] = f[u][2] * (f[v][0] + f[v][1]) % mod;
	}
	
}

int main(){
//FileOpen();

	int n, K;
	io >> n >> K;
	R(i,2,n){
		int u, v;
		io >> u >> v;
		add(u, v);
		add(v, u);
	}
	
	R(i,1,K){
		int x, nodeColor;
		io >> x >> nodeColor;
		col[x] = nodeColor;
	}
	
	DFS(1, 0);
	
	printf("%lld", ((f[1][0] + f[1][1] + f[1][2]) % mod + mod) % mod);
	
	return 0;
}