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  • CF 559C

    (C_{x+y}^y)的公式,DP容斥删多余贡献。

    #include <cstdio>
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int a = (b); (a) <= (c); ++(a))
    #define nR(a,b,c) for(register int a = (b); (a) >= (c); --(a))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Swap(a,b) ((a) ^= (b) ^= (a) ^= (b))
    #define ll long long
    #define u32 unsigned int
    #define u64 unsigned long long
     
    //#define ON_DEBUGG
     
    #ifdef ON_DEBUGG
     
    #define D_e_Line printf("
    ----------
    ")
    #define D_e(x) cout << (#x) << " : " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt", "r", stdin)
    #define FileSave() freopen("out.txt", "w", stdout)
    #include <ctime>
    #define TIME() fprintf(stderr, "
    time: %.3fms
    ", clock() * 1000.0 / CLOCKS_PER_SEC)
    
    #else
     
    #define D_e_Line ;
    #define D_e(x) ;
    #define Pause() ;
    #define FileOpen() ;
    #define FileSave() ;
    #define TIME() ;
    //char buf[1 << 21], *p1 = buf, *p2 = buf;
    //#define getchar() (p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1 << 21, stdin), p1 == p2) ? EOF : *p1++)
     
    #endif
     
    using namespace std;
    struct ios{
        template<typename ATP>inline ios& operator >> (ATP &x){
            x = 0; int f = 1; char ch;
            for(ch = getchar(); ch < '0' || ch > '9'; ch = getchar()) if(ch == '-') f = -1;
            while(ch >= '0' && ch <= '9') x = x * 10 + (ch ^ '0'), ch = getchar();
            x *= f;
            return *this;
        }
    }io;
     
    template<typename ATP>inline ATP Max(ATP a, ATP b){
        return a > b ? a : b;
    }
    template<typename ATP>inline ATP Min(ATP a, ATP b){
        return a < b ? a : b;
    }
    template<typename ATP>inline ATP Abs(ATP a){
        return a < 0 ? -a : a;
    }
    
    const int N = 200007;
    const int mod = 1000000007;
    
    #define int long long
    struct nod{
    	int x, y;
    	bool operator < (const nod &com) const{
    		if(x != com.x) return x < com.x;
    		return y < com.y;
    	}
    }a[N];
    int fac[N], inv[N], n, m, K;
    inline int Pow(int a, int b){
    	int s = 1;
    	while(b){
    		if(b & 1) s = s * a % mod;
    		a = a * a % mod, b >>= 1; 
    	}
    	return s;
    }
    inline void Init(){
    	fac[0] = fac[1] = inv[0] = 1;
    	R(i,2,n + m) fac[i] = fac[i - 1] * i % mod;
    	R(i,1,n + m) inv[i] = Pow(fac[i], mod - 2);
    }
    inline int Calc(int x, int y){
    	if(x < 0 || y < 0) return 0;
    	return fac[x + y] * inv[x] % mod * inv[y] % mod;
    }
    int f[N];
    #undef int
    int main(){
    #define int long long
    //FileOpen();
    //FileSave();
    	io >> n >> m >> K;
    	Init();
    	R(i,1,K){
    		io >> a[i].x >> a[i].y;
    	}
    	sort(a + 1, a + K + 1);
    	a[K + 1] = (nod){ n, m};
    	R(i,1,K + 1){
    		int x = a[i].x - 1, y  = a[i].y - 1;
    		f[i] = Calc(x, y);
    		R(j,1, i - 1){
    			int dx = a[i].x - a[j].x, dy = a[i].y - a[j].y;
    			int del = Calc(dx, dy) * f[j] % mod;
    			f[i] = (f[i] - del + mod) % mod;
    		}
    	}
    	printf("%lld", f[K + 1]);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11612081.html
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