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  • LeetCode Pascal's Triangle

    
    

    Given numRows, generate the first numRows of Pascal's triangle.

    
    

    For example, given numRows = 5,
    Return

    
    
    [
         [1],
        [1,1],
       [1,2,1],
      [1,3,3,1],
     [1,4,6,4,1]
    ]


    public
    class Solution { List<List<Integer>> lastNumberlist = new ArrayList<List<Integer>>(); public List<List<Integer>> generate(int numRows) { if (numRows==0) { return lastNumberlist; } ArrayList<Integer> list=new ArrayList<>(); int num1,num2; list.add(1); lastNumberlist.add(list); if (numRows==1) { return lastNumberlist; } list=new ArrayList<>(); list.add(1); list.add(1); lastNumberlist.add(list); if (numRows==2) { return lastNumberlist; } for (int i = 3; i <=numRows ; i++) { int[] newline=new int[i]; for (int j = 0; j <= i/2; j++) { if (j==0) { newline[j]=1; newline[i-1-j]=1; }else {
                  num1=lastNumberlist.get(lastNumberlist.size()-1).get(j);
                  num2=lastNumberlist.get(lastNumberlist.size()-1).get(j-1);               newline[j]=num1+num2;               newline[i-1-j]=num1+num2; } } list=new ArrayList<>(); for (int j : newline) { list.add(j); } lastNumberlist.add(list); } return lastNumberlist; } }
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  • 原文地址:https://www.cnblogs.com/birdhack/p/4020592.html
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