1 问题
- C++ 中是否允许一个类继承自多个父类?
2 C++ 中的多重继承
-
C++ 支持编写多重继承
- 一个子类可以拥有多个父类
- 子类拥有所有父类的成员变量
- 子类继承所有父类的成员函数
- 子类对象可以当作任意父类对象使用
-
多重继承的语法规则
- 多重继承的本质与单继承相同
class Derived : public BaseA, public BaseB, public BaseC { //... };
-
示例1:多重继承问题一
-
Demo
#include <iostream> #include <string> using namespace std; class BaseA { int ma; public: BaseA(int a) { ma = a; } int getA() { return ma; } }; class BaseB { int mb; public: BaseB(int b) { mb = b; } int getB() { return mb; } }; class Derived : public BaseA, public BaseB { int mc; public: Derived(int a, int b, int c) : BaseA(a), BaseB(b) { mc = c; } int getC() { return mc; } void print() { cout << "ma = " << getA() << ", " << "mb = " << getB() << ", " << "mc = " << mc << endl; } }; int main() { cout << "sizeof(Derived) = " << sizeof(Derived) << endl; // 12 Derived d(1, 2, 3); d.print(); cout << "d.getA() = " << d.getA() << endl; cout << "d.getB() = " << d.getB() << endl; cout << "d.getC() = " << d.getC() << endl; cout << endl; BaseA* pa = &d; BaseB* pb = &d; cout << "pa->getA() = " << pa->getA() << endl; cout << "pb->getB() = " << pb->getB() << endl; cout << endl; void* paa = pa; void* pbb = pb; if( paa == pbb ) { cout << "Pointer to the same object!" << endl; } else { cout << "Error" << endl; } cout << "pa = " << pa << endl; cout << "pb = " << pb << endl; cout << "paa = " << paa << endl; cout << "pbb = " << pbb << endl; return 0; }
-
编译运行
sizeof(Derived) = 12 ma = 1, mb = 2, mc = 3 d.getA() = 1 d.getB() = 2 d.getC() = 3 pa->getA() = 1 pa->getB() = 2 Error pa = 0xbff39374 pb = 0xbff39378 paa = 0xbff39374 pbb = 0xbff39378
-
3 多重继承的问题
-
问题一:通过多重继得到的对象可能拥有不同的地址
- 解决方案:无!
-
问题二:多重继承可能产生冗余的成员
- 当多重继承关系出现闭合时,将产生数据冗余的问题
- 解决方案:虚函数
- 虚继承能够解决数据冗余的问题
- 自建层父类不再关心顶层父类的初始化
- 最终子类必须直接调用顶层父类的构造函数