通常情况下,我们需要去推断一个字符串变量是否为空,今天,我特意做了一个小测试
StringUtils.java:
package com.yx.equipment_collection.utils; import android.annotation.SuppressLint; import android.text.TextUtils; import android.util.Log; /** * * 此类描写叙述的是: String帮助类 * * @author: CS YX * @version:1.0 * @date:2014-10-21 下午2:47:08 */ public class StringUtils { private static final String TAG = "StringUtils"; private static int count = 100000000; public static void checkEmpty1(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str == null || str.length() < 1) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty1 --- " + (end - start)); } @SuppressLint("NewApi") public static void checkEmpty2(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str == null || str.isEmpty()) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty2 --- " + (end - start)); } public static void checkEmpty3(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str == null || str == "") { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty3 --- " + (end - start)); } public static void checkEmpty4(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str == null || str.equals("")) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty4 --- " + (end - start)); } public static void checkEmpty5(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str == null || TextUtils.isEmpty(str)) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty5 --- " + (end - start)); } public static void checkEmpty11(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str != null && str.length() > 0) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty11 --- " + (end - start)); } @SuppressLint("NewApi") public static void checkEmpty22(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str != null && !str.isEmpty()) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty22 --- " + (end - start)); } public static void checkEmpty33(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str != null && str != "") { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty33 --- " + (end - start)); } public static void checkEmpty44(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str != null && !str.equals("")) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty44 --- " + (end - start)); } public static void checkEmpty55(String str) { long start = System.currentTimeMillis(); for (int i = 0; i < count; i++) { if (str != null && !TextUtils.isEmpty(str)) { } } long end = System.currentTimeMillis(); Log.i(TAG, "checkEmpty55 --- " + (end - start)); } }
測试为空例如以下:test
public void test() { String str = ""; Log.i("test", "str=""---"); StringUtils.checkEmpty1(str); StringUtils.checkEmpty2(str); StringUtils.checkEmpty3(str); StringUtils.checkEmpty4(str); StringUtils.checkEmpty5(str); str = null; Log.i("test", "str=null---"); StringUtils.checkEmpty1(str); StringUtils.checkEmpty2(str); StringUtils.checkEmpty3(str); StringUtils.checkEmpty4(str); StringUtils.checkEmpty5(str); str = "null"; Log.i("test", "str="null"---"); StringUtils.checkEmpty1(str); StringUtils.checkEmpty2(str); StringUtils.checkEmpty3(str); StringUtils.checkEmpty4(str); StringUtils.checkEmpty5(str); str = new String(); Log.i("test", "str=new String()---"); StringUtils.checkEmpty1(str); StringUtils.checkEmpty2(str); StringUtils.checkEmpty3(str); StringUtils.checkEmpty4(str); StringUtils.checkEmpty5(str); }
測试结果输入例如以下图:
由此图能够看出方法3(str == "")用时是最少的;其次就是方法1(str.length() < 1)和方法2(str.isEmpty()) ;
方法4(str.equals(""))耗时较多;方法5(TextUtils.isEmpty(str))最耗时
測试非空例如以下:test
public void test1() { String str = ""; Log.i("test", "str=""---"); StringUtils.checkEmpty11(str); StringUtils.checkEmpty22(str); StringUtils.checkEmpty33(str); StringUtils.checkEmpty44(str); StringUtils.checkEmpty55(str); str = null; Log.i("test", "str=null---"); StringUtils.checkEmpty11(str); StringUtils.checkEmpty22(str); StringUtils.checkEmpty33(str); StringUtils.checkEmpty44(str); StringUtils.checkEmpty55(str); str = "null"; Log.i("test", "str="null"---"); StringUtils.checkEmpty11(str); StringUtils.checkEmpty22(str); StringUtils.checkEmpty33(str); StringUtils.checkEmpty44(str); StringUtils.checkEmpty55(str); str = new String(); Log.i("test", "str=new String()---"); StringUtils.checkEmpty11(str); StringUtils.checkEmpty22(str); StringUtils.checkEmpty33(str); StringUtils.checkEmpty44(str); StringUtils.checkEmpty55(str); }
測试结果例如以下图:
如上图所看到的,首先是方法33(str != null && str != "")比較占优势。方法11(str != null && str.length() > 0)和方法22(str != null && !str.isEmpty())整体来说。不相上下;
方法44(str != null && !str.equals(str != null && !TextUtils.isEmpty(str)))较耗时;方法55()还是最耗时
也有人说,用‘==’推断字符串不准确,应该用‘equals’,个人认为String一般都是直接=定义,想必没有几个人定义一个字符串会new出来吧。
为什么TextUtils.isEmpty()耗时最多,查看源代码原来isEmpty()已经推断了‘==null’:
/** * Returns true if the string is null or 0-length. * @param str the string to be examined * @return true if str is null or zero length */ public static boolean isEmpty(CharSequence str) { if (str == null || str.length() == 0) return true; else return false; }
源代码还用于.length()推断,假设你想‘==’不靠谱。推荐使用.length()对于推理方法!
不是单纯的个人意见......谢谢