zoukankan      html  css  js  c++  java
  • HDU 1702 ACboy needs your help again!

    Problem Description
    ACboy was kidnapped!! 
    he miss his mother very much and is very scare now.You can't image how dark the room he was put into is, so poor :(.
    As a smart ACMer, you want to get ACboy out of the monster's labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can't solve my problems, you will die with ACboy."
    The problems of the monster is shown on the wall:
    Each problem's first line is a integer N(the number of commands), and a word "FIFO" or "FILO".(you are very happy because you know "FIFO" stands for "First In First Out", and "FILO" means "First In Last Out").
    and the following N lines, each line is "IN M" or "OUT", (M represent a integer).
    and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully!
     

    Input
    The input contains multiple test cases.
    The first line has one integer,represent the number oftest cases.
    And the input of each subproblem are described above.
     

    Output
    For each command "OUT", you should output a integer depend on the word is "FIFO" or "FILO", or a word "None" if you don't have any integer.
     

    Sample Input
    4 4 FIFO IN 1 IN 2 OUT OUT 4 FILO IN 1 IN 2 OUT OUT 5 FIFO IN 1 IN 2 OUT OUT OUT 5 FILO IN 1 IN 2 OUT IN 3 OUT
     

    Sample Output
    1 2 2 1 1 2 None 2 3
     
    再来一发STL,=.=,队列和栈都用用到
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<limits.h>
    #include<queue>
    #include<stack>
    using namespace std;
    char c[10];
    int x;
    void solve_s(int n)
    {
        stack<int>s;
        while(n--)
        {
            scanf("%s",c);
            if(!strcmp(c,"IN"))
            {
                scanf("%d",&x);
                s.push(x);
            }
            else
            {
                if(!s.empty())
                {
                    printf("%d
    ",s.top());
                    s.pop();
                }
                else
                    printf("None
    ");
            }
        }
    }
    void solve_q(int n)
    {
        queue<int>q;
        while(n--)
        {
            scanf("%s",c);
            if(!strcmp(c,"IN"))
            {
                scanf("%d",&x);
                q.push(x);
            }
            else
            {
                if(!q.empty())
                {
                    printf("%d
    ",q.front());
                    q.pop();
                }
                else
                    printf("None
    ");
            }
        }
    }
    int main()
    {
        int t,n;
        char str[10];
        scanf("%d",&t);
        while(t--)
        {
            scanf("%d%s",&n,str);
            if(!strcmp(str,"FIFO"))
               solve_q(n);
            else
               solve_s(n);
        }
        return 0;
    }
    


  • 相关阅读:
    移动web开发框架研究
    Android客户端缓存机制(文字缓存和多媒体文件缓存)
    edittext实现自动查询,刷新listview
    Android属性动画 nineoldandroids
    android 框架LoonAndroid,码农偷懒专用
    待看
    aidl
    国内外DNS服务器地址列表
    js 防止重复点击
    js 模块化
  • 原文地址:https://www.cnblogs.com/blfshiye/p/5412396.html
Copyright © 2011-2022 走看看